Check??Newbie..HELP!!

This is a discussion on Check??Newbie..HELP!! within the C++ Programming forums, part of the General Programming Boards category; you can test for int's easily but char's and string's are a different story. you must not forget that a ...

  1. #16
    Registered User
    Join Date
    Apr 2002
    Posts
    94
    you can test for int's easily but char's and string's are a different story. you must not forget that a char can be anything that can be inputted via the keyboard....including numbers, symbols and characters.

    if you are more specific with what you are after I might be able to help you...but as I said, I need to know exactly what it is you want to do.

    ohh...just another thing that just clicked to me....you can do a something like this which will only continue until a valid char input has been made.
    Code:
    char ch;
    
      do
      {
         cout << "pls select from the following " << endl;
         cout << " a)  add another word " << endl;
         cout << " b)  find word" << endl;
         cout << " c)  exit " << endl;
         cin >> ch;
    
        switch (ch)
        {
            case 'a' :  addData();   //go to a fnt
                            break;
            case 'b' :  findData ();
                            break;
        }
      } while (ch != 'c');
    hope this helps...
    simple is always an understatement.....

  2. #17
    Unregistered
    Guest

    Question well...

    My expected code:
    Code:
    string s1="end";
       do {
    	  
          cout << "Enter name:";
          cin >> name;
          if (name==s1) //this is working
             break;
    
    	  //while ((name doesnt has alphabets))
    	       cout<<"error"
                                   <<"ur string has a number in it"<<endl;
    		  cout<<"please re-enter the name"<<endl;
    		  cin>>name;//
    this is my first doubt..

    also there is a minor bug,which is buggin me ,as per ur previous code for checking ONLY int ,

    Code:
    cout << "Enter 1st time:";
          cin >> a_time;
    	  while (cin.fail())
     {
        cin.clear();
        cin.ignore (buffer, '\n');
        cout << "pls re-enter number";
        cin >>a_time;       //now for eg if i type 12A  the  output  is "enter   2nd time", pls re-enter number" ie. how should i avoid getting the display message"enter 2nd time"??//
     } 
    
     cout << "Enter 2nd time:";
          cin >> b_time;
    	  while (cin.fail())
     {
        cin.clear();
        cin.ignore (buffer, '\n');
        cout << "pls re-enter number";
        cin >>b_time;
     }
    thanks ......

  3. #18
    Registered User
    Join Date
    Apr 2002
    Posts
    94
    if the user was to input 132A your program will accept and only assign 132 to your a_time...if the user had inputted A123 then cin.fail() would return true and ask you to re-enter the value.

    if the user was to input 12ABC34, then a_time would hold the value of 12 and ignore the rest.

    as for your function with strings...firstly you cant have string s1="end" unless you pre-define it. dont forget a string is just an array of characters terminated with a '\0' character.

    string.h library has a variety of string operations you can use. for example, instead of doing name==s1 (which I dont think should work unless everything is implemented properly) you can and should really get use to doing something like :

    result=strcmp(str1, str2);

    result will contain a -ve number if str1 < str2
    result will contain a +ve number if str1 > str2
    result will contain a zero if str1==str2

    and then you can put in your conditions according to what result returns. you can find alot of information in regards to string handling if you look through a text book dealing with c++.

    something I just remembered may also be useful....try something like this :

    if (letter < 'a' || letter > 'z')

    this may also help with what you want

    sophie
    Last edited by sweets; 04-07-2002 at 04:42 AM.
    simple is always an understatement.....

  4. #19
    Unregistered
    Guest

    No,it isnt!

    Unfortunately sophie thats not the case,
    if i type 13a /13A ,
    its showing me the next cout statement; in my case
    "enter 2nd TIME"//which is the time in seconds//
    and next line its coming "please reenter number"

    also checking of strings, i have predefined
    string s1="end" ,before int main()
    and its working nicely.

    i have used find_first_of funcn,which checks that input is a string but i just dont know how to put it in a while loop,to ask the user to reenter the name
    my present code:

    Code:
    in chk=0;
    int main()
    .
    .
    chk= name.find_first_of("1234567890");
    	  if(chk!=-1)
    	  {
    		  cout<<"error!"
    	                      <<"ur string has a number in it";
    	  }
    thanks .......

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