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what "bitand" do ???

This is a discussion on what "bitand" do ??? within the C++ Programming forums, part of the General Programming Boards category; hello what does "bitand" do in c++ code ? what is that mean : (object_name bitand variable_name)...

  1. #1
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    what "bitand" do ???

    hello
    what does "bitand" do in c++ code ?


    what is that mean : (object_name bitand variable_name)

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    C++ Witch laserlight's Avatar
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    bitand means &

    Just another name, so unless you need it, you might as well use &.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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    Thank You Laserlight,

    what is that mean : (object_name bitand variable_name) ?

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    C++ Witch laserlight's Avatar
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    Oh, then you should read about bit shifting and bitwise operations.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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    What is that mean :
    class_name bitand operator = (const class_name bitant)


    Thanks laserlight

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    But an object is not a variable ! . it is not possible to do bit wise with an object .

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    C++ Witch laserlight's Avatar
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    Quote Originally Posted by codewriter
    What is that mean :
    class_name bitand operator = (const class_name bitant)
    Do you have any special reason to use bitand instead of & when I already recommended just using &? Are you learning C++ through a book or something? If so, which book?

    Quote Originally Posted by codewriter
    But an object is not a variable ! . it is not possible to do bit wise with an object .
    The term "object" can include objects of built-in types like int. But you probably have objects of class type in mind, in which case there is operator overloading.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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    This a part of the code :
    bool DrawRect(const TRect bitand SrcRect, int x, int y)

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    TRect is a name of a class

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    C++ Witch laserlight's Avatar
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    Please answer my questions.

    The problem is that this should be a fairly easy question to answer, as long as you have had a proper introduction to C++. Otherwise, my answer will be meaningless to you except as an answer to a trivia question.
    oogabooga likes this.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  11. #11
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    If bitand is exactly the same as & (whether meaning bitwise-and, address-of or reference) then
    Code:
    class_name bitand operator = (const class_name bitand)
    is just a really stupid way of saying
    Code:
    class_name& operator=(const class_name&)
    The cost of software maintenance increases with the square of the programmer's creativity. - Robert D. Bliss

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