what "bitand" do ???

hello
what does "bitand" do in c++ code ?


what is that mean : (object_name bitand variable_name)

bitand means &

Just another name, so unless you need it, you might as well use &.

Thank You Laserlight,

what is that mean : (object_name bitand variable_name) ?

Oh, then you should read about bit shifting and bitwise operations.

What is that mean :
class_name bitand operator = (const class_name bitant)


Thanks laserlight

But an object is not a variable ! . it is not possible to do bit wise with an object .

Originally Posted by codewriter

What is that mean :
class_name bitand operator = (const class_name bitant)

Do you have any special reason to use bitand instead of & when I already recommended just using &? Are you learning C++ through a book or something? If so, which book?

Originally Posted by codewriter

But an object is not a variable ! . it is not possible to do bit wise with an object .

The term "object" can include objects of built-in types like int. But you probably have objects of class type in mind, in which case there is operator overloading.

This a part of the code :
bool DrawRect(const TRect bitand SrcRect, int x, int y)

TRect is a name of a class

Please answer my questions.

The problem is that this should be a fairly easy question to answer, as long as you have had a proper introduction to C++. Otherwise, my answer will be meaningless to you except as an answer to a trivia question.

If bitand is exactly the same as & (whether meaning bitwise-and, address-of or reference) then

Code:

class_name bitand operator = (const class_name bitand)

is just a really stupid way of saying

Code:

class_name& operator=(const class_name&)