Need help with Multiply and Divide operators

Alright, so I'm using switches and -

Code:

#include <iostream>


using namespace std;


int x;
int a;
int b;
int e = 100;
int f = 50;
int g = 10;
int h = 10;


    void Add()
{
    cout <<"\n Added 100 to " << a + b + x<< "\n";
    cout << "Your final result is -\n" << e + x + a + b;
}
void Subtract()
{
    cout <<"\nSubtract 50 from " << x + a + b << "\n";
    cout << "Your final result is -\n" << x + a + b - f;
}
void Multiply()
{
    cout <<"\nMultiplied 10 with " << x + a + b << "\n";
    cout << "Your final result is -\n" << x + a + b * g;
}
void Divide()
{
    cout <<"\nDivided 10 to " << x + a + b << "\n";
    cout << "Your final result is -\n" << x + a + b / h;
}


int main()
{
    cout << "Please input a number: ";
    cin >> x;
    cin.ignore();


    cout << "\nYou have entered " << x << ". Please hit ENTER to continue";
    cin.get();


    cout << "\nPlease enter two numbers to be added to " << x << " :";
    cin >> a >> b;
    cin.ignore();
    cout << "\nThe total is - " << a + b + x << ". " << "Please hit ENTER to continue";


    cin.get();


    int c;


    cout<<"1. Add\n";
    cout<<"2. Subtract\n";
    cout<<"3. Multiply\n";
    cout<<"4. Divide\n";


    cin>> c;


    switch (c) {
    case 1:
        Add();
        break;
    case 2:
        Subtract();
        break;
    case 3:
        Multiply();
        break;
    case 4:
        Divide();
        break;
    default:
        cout<<"Input not recognized. Quitting now\n";
        break;


    cin.get();
    }


}

Add and Subtract works well with no problem. But it is Multiply and Divide that is making my head scratch.

If I put 100 into x, a and b and use Multiply to multiply 300 by 10, it doesn't return 3000, it returns 1200...

For Divide, if I put the same number, 100, into x, a and b and use Divide to divide 300 by 10, it doesn't return 30, it returns 210...

Does anyone know how to fix this?

> cout << "Your final result is -\n" << x + a + b * g;
Perhaps some extra ( ) ?

cout << "Your final result is -\n" << (x + a + b) * g;

Originally Posted by Salem

> cout << "Your final result is -\n" << x + a + b * g;
Perhaps some extra ( ) ?

cout << "Your final result is -\n" << (x + a + b) * g;

It works! Thanks for the help

+1 to you.

C++ follows basic rules of algebra.
Also, global variables are bad.