Thread: change array size

Hi,

I am a real beginner, and I am having trouble, can someone please help. I have to complete some code to change the size of an array to a new size (newS) that is specified by the argument in program that tests it. The program that I have to code uses a template and I'm a bit unsure how to go about this. I think I need to use 'new' but not sure how.

I have to complete the code for public function void grow(int);
template <class BType, class IType>
void Array<BType, IType>::grow(int newS)
{
// I need to code this, everthing else is already done
}


The program for testing this is
int main(void)
{
int i;
Array<int> A(5);
ofile.open("A11.out");
for (i = 0; i < 5; ++i)
A[i] = i;
printIt(A, "Original");
A.grow(10);
for (i = 5; i < 10; ++i)
A[i] = 2 * i;
printIt(A, "Increased");
A.grow(4);
printIt(A, "Decreased");
ofile.close();
return 0;
}

Thanks

you're right about using the "new" operator ......

the trick to it is to declare the original array dynamicaly, meaning on the "heap" or (so called "free store")

Code:

 int Size = 20;

 int * IntArray[Size] = new int[Size];

i believe after wards you can change the size of an array dynamicaly depending on the user's input.

hope that helps...

ps. you can also try "linked lists"

Regards,
matheo917

void Array<BType, IType>::grow(int newS)
{
//assume thatyou have an pointor in Array<BType,IType>:
//Type* old,
Type *tmp=new Type[newS];
//copy the elements to the new one that on the heap
......
delete old;
old =tmp;
}

i'm a beginner too.

hope that helps...

I have got a little further....This is the code I have used, however I don't know how to retain the original values - do I somehow have to copy the original array first? I tried to do this but it didn't work so I must not be doing it right, any ideas???

template <class BType, class IType>
void Array<BType, IType>::grow(int newS)
{
hibnd = newS - 1;
arrayData = new BType[newS];

}

output.....

Original:0,1,2,3,4.

Increased:4325492,4325436,0,0,0,10,12,14,16,18.

Decreased:4325492,4325436,0,0.

>do I somehow have to copy the original array first?

Create a pointer to the original array, then use 'new' to create the new array. Next copy the data from the old array to the new array. Finally use 'delete' to free the old array.