
far too many uninitialised variables, set things to 0 as often as you can, at least then you have a known value to work with. and at least as a basic protection against bad user input in this case., this thread is littered with examples of you just not taking any notice of good advice given.
and ay caramba :
Code:
int simplify(int x2 ,int y2 ,int gcd ,int a ,int b )
{
a= x2/gcd;
b= y2/gcd;
return simplify;
}
What on earth do you think simplify will be?

Code:
#include "stdafx.h"
#include <iostream>
using namespace std;
int simplify(int x2 ,int y2 ,int gcd ,int a ,int b )
{
a= x2/gcd;
b= y2/gcd;
return simplify( x2, y2, gcd, a,b);
}
int gcd(int x2, int y2)
{
int i;
int gcd2;
for (i=1; i<=x2; i++)
{
if((x2%i==0) && (y2%i==0))
gcd2 = i;
}
return gcd2;
}
int multiply()
{
int numerator,denominator,numerator2,denominator2 ;
int x;
int x2, t2;
int c;
int d;
cout<<"Input the numerator and denominator of a fraction separated by spaces :"<<endl;
cin>>numerator;
cin>>denominator;
cout<<"Input the numerator and denominator of a fraction separated by spaces :"<<endl;
cin>>numerator2;
cin>>denominator2;
cout<<"Input instruction*_" << endl;
x2 = numerator*numerator2;
t2 =denominator*denominator2;
x=gcd( x2, t2);
simplify( x2 , t2 ,x , c , d);
cout<<"("<< numerator << "/"<<denominator <<") * ("<< numerator2 <<"/"<< denominator2 <<") = " << c << "/" << d;
cout << "\n";
return 0;
}
int main()
{
multiply();
system ("PAUSE");
}

right erm, yea.
If you want good help, its a two way thing, are you really so unbelievably lazy and rude that you think its ok to just dump wedges of code by way of a response every time? And then expect to get expert help from the board members, when its a bloomin sunday too.
Why not add some words too?????

At this point, you are just guessing.
Work with us  what is it that you fail to understand?

rogster Im not rude... I sitting on this project and really have enough . im dont want to be a programmer its only one of my subjects which i need to pass.. I dont even like it. u think for me its easy to ask like an idiot 10 times this same.. ..
i will be never a programmer..
i really need help to finish it..

Well, even more than you not wanting to be a programmer, we don't want to be robots :)
So, when you post your code, tell us: what's wrong?

Regardless, the subject is there for a reason. Therefore, you need to make sure you acquire the abilities needed to pass the course. It doesn't matter whether you like it or not.
Tell us what you are having problems with  in details, or just forget about getting any help. We cannot help you if you do not work with us, and we will not do your homework for you.

why return simplify( x2, y2, gcd, a,b);
didnt return the values to multiply

What do you expect it to do? That's a function call.

well its a bit of a shaky one, but an oft quoted:
"To ask may be but a moment's shame, not to ask and remain ignorant is a lifelong shame"
We don't mind how often you ask questions, that is good, and it is true that by teaching you learn, so like i say it is a two way thing, I would not bother answering at all otherwise.
You just have to consider how it looks when code is posted without any other message, It comes across very badly, no one is paid here remember.
Fair enough you dont like programming, but as Elysia points out it is a pre requisite of your course, I hated half the crap i had to learn too,( my study was nothing to do with IT or technical by the way) but it is a case of shifting your mindset and concentrating on the long term goal.

To be honest, the problem you are facing is that you are not reading.
You want to return two values from a function. We say: "use references." I even gave you an example in post #18: http://cboard.cprogramming.com/cplus...ml#post1090046
But nowhere in your code do I see you using references.

Code:
#include "stdafx.h"
#include <iostream>
using namespace std;
int simplify(int x2 ,int y2 ,int gcd ,int a ,int b )
{
a= x2/gcd;(simplify its counting a and b)
b= y2/gcd;
return (x2,y2,gcd,a,b); now its returning the x2,y2,gcd,a,b but the value of and b its different
}
int gcd(int x2, int y2)
{
int i;
int gcd2;
for (i=1; i<=x2; i++)
{
if((x2%i==0) && (y2%i==0))
gcd2 = i;
}
return gcd2;
}
int multiply()
{
int numerator,denominator,numerator2,denominator2 ;
int x;
int x2, t2;
int c;
int d;
cout<<"Input the numerator and denominator of a fraction separated by spaces :"<<endl;
cin>>numerator;
cin>>denominator;
cout<<"Input the numerator and denominator of a fraction separated by spaces :"<<endl;
cin>>numerator2;
cin>>denominator2;
cout<<"Input instruction*_" << endl;
x2 = numerator*numerator2;
t2 =denominator*denominator2;
x=gcd( x2, t2);
simplify( x2 , t2 ,x , c , d); here im sending arguments to simplify(1) 3)its returning the values here
cout<<"("<< numerator << "/"<<denominator <<") * ("<< numerator2 <<"/"<< denominator2 <<") = " << c << "/" << d;
cout << "\n";
return 0;
}
int main()
{
multiply();
system ("PAUSE");
}
Why c and d its 0??????

Why are you not listening?
Go read up on the command operator, passing by value and passing by reference.
