Thread: How to input char variables in the same line?

Originally Posted by Lucas525

I get what you want to say but when I press "a" the input MUST stop and the program goes to output, in other words, it cannot allow me to input any more letters after "a".

Ah... then you have to use unbuffered input, which is not provided by the standard libraries. This FAQ will show you several ways to get an unbuffered character. That way the program ends immediately after pressing 'a'.

Interestingly enough, with what you showed me, concerning something like "pdfjka ifhf" everything after 'a' isn't going to be processed anyway.

I hope I helped.

It's done! getche() was the command I was looking for. So this is the program:

Code:

#include <iostream>
#include <conio.h>
#include <cstring>


using namespace std;


int main()
{
    char suglasnici [43] = {'b','c','d','f','g','h','j','k','l','m','n','p','q','r','s','t','v','w','x','y','z','B','C','D','F','G','H','J','K','L','M','N','P','Q','R','S','T','V','W','X','Y','Z','\0'};
    char slovo;
    int sam = 0;
    int sug = 0;
    int i;
    cout << "Upisite slova. Za kraj upisite malo slovo a: " << endl;
    do
    {
        slovo = getche();
        cout << " ";
        if (slovo=='a'||slovo=='e'||slovo=='i'||slovo=='o'||slovo=='u'||slovo=='A'||slovo=='E'||slovo=='I'||slovo=='O'||slovo=='U')
        {
            sam++;
        }else
        {
            for(i=0;i<strlen(suglasnici);i++)
            {
                if(slovo == suglasnici[i])
                {
                    sug++;
                }
            }
        }
    }while(slovo!='a');
    cout << "\nBroj samoglasnika je: " << sam << endl;
    cout << "Broj suglasnika je: " << sug << endl;
    return 0;
}

The variables and texts are all in croatian. I know I could have made the suglasnici(consonants) variable as a string so it would be shorter but it's ok as long as it's working...