hekp with programming

OK, so I see a lot of problem here.
First, madscientist posted in the C++ section (not C!), and specifically asked for help in C++ (not C!).
Secondly, cauberong09 dumped a solution to a problem directly (which is discouraged), which has a lot of defects (for example, undefined behavior), and finally posted code in C (not C++!).

So let's clear this up now.
Is this supposed to be C or C++?
C does not belong in the C++ forum and vice versa. Therefore, it is strongly discouraged to post examples or code in C in the C++ forum or vice versa. If this is indeed supposed to be C++, then cauberong09's code does not belong here, nor should it have been posted in the first place.
If this is indeed C, then this post is in the wrong forum.

Also, cauberong09. It is understandable that you want to learn more, and that is fine. I would recommend that you actually read people's problems and the answers to them instead of dumping code. You will learn a lot. I guarantee it.

it is supposed to be c++..
so i got a little work done myself and i got this code which does not work right now and i can't find the problem... it compiles without errors but when i run it number of consonants or "integer count" turns out to be zero.. could the problem be fact that im using croatian letters?

Code:

---

#include <stdio.h>
#include <conio.h>
#include <ctype.h>
#include<stdlib.h>
int main()
{
    system("cls");
    int count=0;
    char ce;
    printf("Enter a charracter:");
    do
    {
        ce=getche();
        char t = tolower(ce);
        if (t == 'q' && t == 'w' && t == 'r' && t == 'z' && t == 'p' && t == 'š' && t == 'đ'
        && t == 's' && t == 'd' && t == 'f' && t == 'g' && t == 'h' && t == 't'
        && t == 'j' && t == 'k' && t == 'l' && t == 'č' && t == 'ć' && t == 'ž'
        &&t == 'y' && t == 'x' && t == 'c' && t == 'v' && t == 'b' && t == 'n' && t == 'm')
            count++;
    }
    while (ce!='a');
   
    printf("\nNumber of consonants:%d",count);
    getche();
    system("pause");
}

---

i went with this because the last program that worked with condition " if (t!='a'&&t!='u'&&t!='i'&&t!='o'&&t!='e')" counted "space" and "enter" keys as consonants...

You need to brush up on your boolean logic.

> t == 'q' && t == 'w'
If t is 'q', then it won't be 'w' will it?

Perhaps try it with || rather than &&

Quote:

---

it is supposed to be c++..

---

Just so you know, it's really not; there is not a single line of that that's actually C++; it's all vanilla C (with the exception of the antiquated conio.h header thrown in there just so you can avoid running this from the command line as it should be, or configuring your IDE to not close console windows when debugging).