Thread: Need Help Passing an Array as a Parameter

Code:

#include <Windows.h>

struct BaseClass 
{
    private:
    protected:
    public:
        virtual void ReservedFunction() {} 
};
template <typename TYPE> struct DerivedClass : public BaseClass 
{ 
    private:
    protected:
    public:
        TYPE                            Value;


        template <typename TYPE> DerivedClass(const TYPE & in__Source) : Value(in__Source) {}
};
template <typename TYPE> TYPE ConvertParameter(BaseClass * in__Source)
{
    DerivedClass<TYPE> * ReturnValue = dynamic_cast<DerivedClass<TYPE> *>(in__Source);
    return ReturnValue->Value;
}
template <typename TYPE> DerivedClass<TYPE> * BuildParameter(const TYPE in__Source)
{
    DerivedClass<TYPE> * ReturnValue = new DerivedClass<TYPE>(in__Source);
    return ReturnValue;
}


struct ArrayFunction
{
    private:
    protected:
    public:
        ArrayFunction(BaseClass ** in__Array)
        {
            in__Array++;
        }
};


int main()
{
    BaseClass * Array[3];
        Array[0] = BuildParameter<int>(14);
        Array[1] = BuildParameter<double>(5.2);
        Array[2] = BuildParameter<char *>("string");


    ArrayFunction Function(Array);


    return 0;
}

I am able to make an array with any values using smart pointers and dynamic_cast. But the only problem I am having is that I am not able to use the array index when I pass it into a function. I am currently using the increment operator ++ to move through the list but I would like use the array index to move through it.

you can pass a real array (not just a pointer to the first element) to a function by declaring your function like this:

Code:

template<typename T, int N>
void function(T (&t)[N]);

you can replace the type parameter with an explicit type and get the same effect.

Thanks for that but now I am having problems with the ConvertParameter function.

I tried changing the parameter in that function to accept a real to one of the elements in the array but I am not able to set the value in the array.