change pointer of an array

I have two arrays.
char array1[64]="Hello World" //left out bytes are padded with NULL
char array2[64]="Nothing to see here"//left out bytes are padded with NULL

Now I want to copy all the contents of array1 to array2 but I don't want to copy the data itself. How can I change the pointer of Array2?

If there is not a convenient way to do this, please tell me about an pointer array. How to initialise it and all?

Quote:

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Originally Posted by Swoorup

Now I want to copy all the contents of array1 to array2 but I don't want to copy the data itself. How can I change the pointer of Array2?

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That would waste the space originally used by array2..but a simple assignment should work.
It would be the same if array2 was declared as a char* .

Thank you! I just got to think about it. But why is this not working
char *Array1[64]=malloc(sizeof(char)*64);


This is the error I am encountering
1 IntelliSense: initialization with '{...}' expected for aggregate object c:\users\sueren\documents\visual studio 2010\projects\ecs project\dynamicadj\main.cpp 25 34 K2Master

Quote:

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Originally Posted by Swoorup

Now I want to copy all the contents of array1 to array2 but I don't want to copy the data itself.

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That is a contradiction since copying the contents of array1 to array2 means copying the data itself.

Quote:

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Originally Posted by Swoorup

How can I change the pointer of Array2?

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You have two arrays. I don't see any pointers.

Quote:

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Originally Posted by Swoorup

If there is not a convenient way to do this, please tell me about an pointer array. How to initialise it and all?

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Perhaps what you want to do is to make array2 a pointer instead (and hence rename it), and then simply get this pointer to point to the first element of array1.

Quote:

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Originally Posted by manasij7479

a simple assignment should work

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No, assignment to an array is not allowed.

Quote:

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Originally Posted by Swoorup

Thank you! I just got to think about it. But why is this not working
char *Array1[64]=malloc(sizeof(char)*64);

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Remove the [64] here...and for C++ you'd need a cast.

It is better to use new anyway..

Code:

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char* array1 = new char[64];

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Quote:

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Originally Posted by laserlight

No, assignment to an array is not allowed.

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Hmm... I didn't know that.
Just thought it was..because I had done it with pointers.
Thanks for the correction... err.. Your Highness ! :P

Quote:

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Originally Posted by manasij7479

Remove the [64] here...and for C++ you'd need a cast.

It is better to use new anyway..

Code:

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char* array1 = new char[64];

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Huh, then how will I transverse through the elements of the array?

Quote:

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Originally Posted by Swoorup

Huh, then how will I transverse through the elements of the array?

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By a loop...
*(array1+n) <--Vary n from 0 to 63 to get the elements.
(I think indices are allowed too..but I'm not very fond of using them with pointers)

I am sorry but this is getting me a bit confused. Suppose I want to access *array2[4] then what do I have to write.
And will array[0] contain the address to the first element?

>Suppose I want to access *array2[4]
Do you have an array of pointers ..or an array of characters ? ...It array2[4] isn't a pointer..the code is faulty.

>And will array[0] contain the address to the first element?
Yes

Quote:

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Originally Posted by manasij7479

By a loop...
*(array1+n) <--Vary n from 0 to 63 to get the elements.
(I think indices are allowed too..but I'm not very fond of using them with pointers)

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I am not very fond of writing *(array1 + n) when array1[n] is clearer. If you want to loop by incrementing an array index, use index notation.

Quote:

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Originally Posted by Swoorup

Suppose I want to access *array2[4] then what do I have to write.

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You would write *array2[4], of course :)

I suggest that you post an updated code snippet, and tell us (in words) what exactly you want to access.

Okay here is what I have

Code:

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char Array1[64]="Hello World";

/* Now how to make another pointer array which holds the data of Array1*/

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Here is an example:

Code:

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char Array1[64] = "Hello World";
char* p = Array1;
std::cout << p[0] << std::endl;

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Note that p is not a "pointer array". p is a pointer to char. It is not that p "holds the data of Array1", but that p points to the first element of Array1.

Wooty!!! thanks a lot.

Thank you guys!

Why not use std::string or std::vector or std::array?