well data types have limits you know.
and maybe that number that you get is the actual
answer if you want trailing zeros do this after setprecision:
Code:#include <iostream.h> #include <stdlib.h> #include <string.h> #include <conio.h> #include <iomanip.h> int main() { int a; cout << setprecision(250); cout << setiosflags(ios::showpoint); double pi = 1/2.545584412*8; cout << pi; cout << "\n"; system("pause"); return 0; }
Last edited by xlnk; 03-31-2002 at 08:50 PM.
the best things in life are simple.
Maybe, you should use a different language if you want that much precision. I think it is COBOL or FORTRAN that don't give limits on data types size. Not sure though.
Ya, the equation is not exactly accurate. Thanks.Originally posted by xlnk
well data types have limits you know.
and maybe that number that you get is the actual
answer if you want trailing zeros do this after setprecision:
Code:#include <iostream.h> #include <stdlib.h> #include <string.h> #include <conio.h> #include <iomanip.h> int main() { int a; cout << setprecision(250); cout << setiosflags(ios::showpoint); double pi = 1/2.545584412*8; cout << pi; cout << "\n"; system("pause"); return 0; }
no problem.
the best things in life are simple.
