Hello,
I understand at the first cout i get the address of the third element
but i dont understand what is this big number i get on the second cout.
Code:#include <iostream> using namespace std; int main() { char buf[5]="abcd"; cout << ((unsigned int*)&buf[2]) << endl; // 003AF6F5 the address cout << *((unsigned int*)&buf[2]) << endl; // 2281727075 ? return 0; }
Using Windows 10 with Code Blocks and MingW.
Print it in hex, then look up hex pairs in your ASCII table.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
I already thought about it and in hex it gives 89006463.
Ah ok so its in inversed order 63=c, 64=d, 00=this must be the terminating zero and 89 is just some garbage?
Is that it?
Using Windows 10 with Code Blocks and MingW.
Correct.
Originally Posted by Adak
Thank you,
and how come that its in inversed order but if you print out the chars they are not?
Using Windows 10 with Code Blocks and MingW.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
