Thread: Symmetrical Number Pyramid Help Please

I would suggest working it out in steps.

1. figure out how you would print "* * * 1" if 4 is entered.
2. Next figure out how you would print the next line, " * * 2 1 2".

After that you should be able to use the same algorithm to print the rest.

I forgot to say that the "*"s are not part of the out put they are just to keep the spaces for some reason the spaces went away and this happened:
1
2 1 2
3 2 1 2 3
4 3 2 1 2 3 4
Sorry for that confusion I should of clarified that first.

No problem, you would go about it the same way. Also, I noticed your while loop is not doing what you think it's doing, you need brackets.

So, I have tweaked it some and now I have it giving the out put
1
212
23123
2341234

I am having a major pain trying to figure out how to make the 2nd inner loop reverse the number order and make the out put take on the form of a triangle. Maybe its because of frustration.

Code:

#include <iostream>
#include <iomanip>
using namespace std;


int main ()
{
    int n , i , j , k;
    
        cout << "Enter an integer between 1 and 15:" << endl;
            cin >> n;
        cout << endl;
    
    while ( n < 0 || n > 16 )
    {
        cout << "Invalid input! Input must be between";
    }
    
    for ( i = 0 ; i < n ; i++ )
    {
        for( j = 2 ; j <= i + 1 ; j++)
        {
            cout << setw(3) << j;
        }
            for ( k = 1 ; k <= i + 1 ; k++ )
            {
                cout << setw(3) << k;
            }
        
        cout << endl;
    }
    
return 0;
}

Instead of counting up your j for loop, count down. It should print

1
21
321
4321