Display all characters that lie between two given indices

Hello, everyone.

I consider myself new to C++ and I have tried to google for it and all it come up with is for string which I think my teacher want me to use c-string. Also, I have look in the textbook and I can't find any similar exercise. This is what I came up with

Code:

char str1[200]= {0};
    for (int n = 0 ; n < begin_display; n++)
    {
        str1[n] = str[n];
    }
    return str1[200];

and here is example:

enter a string: My brother Joseph is married.
Please enter the beginning index: 5
Please enter the ending index: 12
other Jo



Thank you for your help. I'm greatly appreciate it

If you only intend to print, then you don't need to copy. You can adapt your loop to print character by character, starting from the beginning index and stopping at the ending index.

Be careful of the possibility that the indices given might be out of range.

Originally Posted by laserlight

If you only intend to print, then you don't need to copy. You can adapt your loop to print character by character, starting from the beginning index and stopping at the ending index.

Be careful of the possibility that the indices given might be out of range.

I have think of that ,but I couldn't make it work. The output is some random characters and it also print characters that outside my two given indices too. For example, My br%%%%%%%seph is married.

Originally Posted by witt

I have think of that ,but I couldn't make it work. The output is some random characters and it also print characters that outside my two given indices too. For example, My br%%%%%%%seph is married.

We are not mind readers, you are going to have to post what you tried. In the mean time read through Lesson 3: Loops and Lesson 9: C strings.

I got the first part but i tried everything on the second part. nothing work. please help!!

Code:

  else if (choice == 3)
    {
        cin.ignore();
        cout<<"How many characters from the beginning of the string do you want to display? ";
        cin>>begin_display;

        if (strlen(str) < begin_display)
            printf("Error: too many characters.\n");
        else
        {
            choicethree(str, begin_display);
            printf("%s\n",str);
        }
    }
  else if (choice == 4)
    {
        cin.ignore();
        cout<<"How many characters from the end of the string do you want to display? ";
        cin>>end_display;

        if (strlen(str) < end_display)
            printf("Error: too many characters.\n");
        else
        {
            choicefour(str, end_display);
            printf("%s\n",str);
        }
    }
void choicethree(char str[], int begin_display)
{
    
    for (int n = begin_display ; n < strlen(str); n++)
    {
        str[n] = '\0';
    }
    
}
void choicefour(char str[], int end_display)
{
    int left;
    left = strlen(str) - end_display;


    for (int i =  0; i < (strlen(str) - end_display) ; i++)
    {
        str[i] = '\0';
    }
    
}

No, you do not seem to be getting this. You need to:

1. Ask for string input.
2. store in char array, see the getline method
3. Ask for start and stop values and bounds check them
4. Iterate through your char array, printing each char individually, from start value to stop value

Attempt these steps and then post the code if you still have problems.

Also, get rid of printf. There is absolutely no reason for it to be there.