I was trying to get a variable to represent all 1's. here is my code:
unsigned long long x;
x = ~0;
cout << x << endl;
when x is printed, it give me 18446744073709551615. I plug that into a calculator and it spits out a 1 followed by 64 zeros. Number 1. I thought long long was 64 bits (on a 32 bit machine) and not 65 and 2. why is it not all 1's? Is x the correct value and I just am not printing it out correctly?
Last edited by redhawk87; 09-21-2011 at 09:20 PM.
ok, I tried printing it out using printf("%x", x) and printf("%d",x) and got 0xFFFFFFFF and -1 respectively. So it looks like it is working. So my question is, why does cout print a wrong value? Also does printf only print 32 bits? If so how can I get all 64 bits printed fairly easily?
Take a look at How to format your output using iomanip.
Originally Posted by anduril462
Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.
I plugged that into my calculator and it spits out 64 1s for the binary representation. Logically, looking at the decimal representation, this number must be odd, so it is impossible for the last bit to be a 0. I suspect a data entry error.
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