Thread: Please help me using strchr

Here;'s the problem:

write a program that inputs several lines of text and uses function strchr to determine the total number of occurrences of each letter of the alphabet in the text. Uppercase and lowercase letters should be counted together. Store the totals for each letter in an array, and print the values in tabular format after the totals have been determined.

Example Output:

enter strings:

in the world
Mother Nature
(etc,,)

A= 1
D=1
E=3
M=1
O=2
and so on..

please help me guys and thank you

Here's my code for that.please correct my codes:

Code:

#include<iostream>
#include<ctype.h>

using namespace std;

int main()
{

char word[500];
int cnt=0;
char *search;
char find='q';

    cout<<"Enter strings (ctrl+z to stop)"<<endl<<endl;
    
    while(gets(word)!=NULL){

if(search=strchr(word,find))
{
 cnt++;
 while(search=strchr(search+1,find))
 cnt++;
}

}
cout<<cnt<<endl;

    
system("pause");

}

1. You're using a char array instead of a string.
2. You misspelled "getline" as "gets".
3. You need to count every letter that comes in, rather than just the letter q.
4. That means you'll need to go through every character typed in, and check whether it is a letter or a non-letter.
5. If it is a letter, you'll have to add to a counter for that letter.

Also, note that 'find' can potentially have conflicts when used in C++ code; being a standard algorithm and also a member of almost everything in the std library.

I have finish it in other way . . .
but can u help me how to stop looping using ctrl + z

Here's my code:

Code:

char text[5][80];
    char *searchPtr;
    int character[26]={'\0'};
    int count =0;
    int i,j;
    
    cout<<"Enter strings (ctrl + z) to stop: \n\n";
    

   for(i=0;i<=5;i++){
                       gets(&text[i][0]);
                    }
    for(i=0;i<=5;i++){
                       for(j=0;text[i][j]!='\0';j++){
                       text[i][j]=tolower(text[i][j]);
                       }
                       }
                       for(i=0;i<=25;i++){
                       for(j=0,count=0;j<=5;j++){
                       searchPtr=&text[j][0];
                       while ( searchPtr = strchr( searchPtr, 'a' + i ) ) {
                       ++count;
                       searchPtr++;
                       }
                       }
                       character[i]=count;
                       }
                                              
                       cout<<endl<<endl;
                       for (i = 0; i <= 25; i++) {
                        cout<< "(";
                        cout<< (char) ('A' + i);
                        cout<< " , ";
                        cout<< (char) ('a' + i);
                        cout<< ") = ";
                        cout<<(int)(character[i]);
                        cout<< endl;
                        }

If you plan to read until EOF, then you need to check whether the input string is still valid, rather than reading six lines come hell or high water (even though you only have room for five lines of text). So read in some text into a buffer, then process that buffer, then read in some text into a buffer, then process that buffer, then read in some text into a buffer, then process that buffer, etc until cin is bad (or, perhaps, while cin is good).