a2 has a local scope. When main() returns, a2 ceases to exist. So that local scope is associated with the main() function. Some people describe this as "function scope"
a2 has a local scope. When main() returns, a2 ceases to exist. So that local scope is associated with the main() function. Some people describe this as "function scope"
Pardon if I'm missing the answer in that, but my question is which one is true:Originally Posted by grumpy
orIt is very true.So is this untrue then? [...]A local variable by definition has local scope, a non-local variable by definition cannot have local scope.
a = a + 2; //This uses a2; it is nonlocal to this block, but it has local scope and is currently the only a in scope
They are both true, although personally I would not have used quite the wordings that tabstop did.
a2 is within the scope associated with the function main(), and hides a1 (at file scope). The body of the while loop within main() defines a new scope, That new scope is within the scope associated with main(), so can access a2 - another a (called a3) is introduced within that scope.
I don't like it either, but I was stuck with the nouns listed in the C++ standard.
This is just one of those topics that are hard to express within the confines of the standard's grammer. Eh, I think the question has been answered, unless the OP has something else he is confused about.
Warning: Some or all of my posted code may be non-standard and as such should not be used and in no case looked at.
