i dont understand this bug, please help me :(

my project is to code a maze game and i decided to include some puzzle elements. my group and i decided that we would have characters that have different properties. for example, pushable characters, characters that you can only pass through once, teleporting characters etc. '$' is supposed to be the character that only allows you to pass through it once, then it will turn into '#' which is an immovable wall. however, when i use gotoxy to move to the $ character, and change it to '#', it does change but the player still can pass through it freely. >.<
The code for the change is this :

Code:

if (move == 'd' || move == 'D')
	{
		if (grid[_y][_x+1] == ' ')
		{
			gotoxy(_x, _y);
			cout << " ";
			_x++;
			gotoxy(_x, _y);
			cout << "@";
		}
		else if (grid[_y][_x+1] == '$')
		{
			gotoxy(_x, _y);
			cout << ' ';
			_x++;
			gotoxy(_x,_y);
			cout << '#';
			_x++;
			gotoxy(_x,_y);
			cout << '@';
		}
		else if (grid[_y][_x+1] == '&')
		{
			gotoxy(_x, _y);
			cout << " ";
			_x++;
			gotoxy(_x,_y);
			cout << "^";
			_x++;
			gotoxy(_x,_y);
			cout << "@";
		}
	}

more info: i have a global char grid[100][100] declared and i used strcopy to copy the text game stages into it. then printing it out with a for loop. help would be greatly appreciated! thanks!

Your problem will be in code that detects a '#' and prevents the player from moving through it. You have not shown such code, but presumably it is functioning incorrectly.

Incidentally, in C++, names beginning with an underscore are reserved for use by the implementation (as names that may be placed in the global namespace). That means you should not give variables (or anything else) a name beginning with an underscore. Doing so can mean your code has undefined behaviour.

thanks for the response, i'll change the underscore.

there is no code detecting the '#'. I didnt put a code detecting a '#' because i dont need it to do anything if the player is moving straight into a '#'. the player will just stay at the current coordinates and nothing will happen to the '#' o.o

You print a #, but you don't change the thing in the array to # (it's still $), so your future checks won't complain about it.

hmm, i thought so. thanks!

now that the problem is identified, how do i fix it x.x

if im not wrong, i have to go into the copied string, find the character '$', erase it and change it to '#'. but i have no idea how to do that :x

Originally Posted by Grey Kliche

hmm, i thought so. thanks!

now that the problem is identified, how do i fix it x.x

if im not wrong, i have to go into the copied string, find the character '$', erase it and change it to '#'. but i have no idea how to do that :x

If you don't know how to do that, then how did you make the maze in the first place?

strcpy(grid[], "####################$############");
o_o

Originally Posted by Grey Kliche

strcopy (grid[], "####################$############");
o_o

That ... might work, depending on how you set up your array, assuming you spelled strcpy correctly and didn't actually put the brackets in. Normally we use = to put things into variables.

it works. i used this to print the stage out:

Code:

for (int i=0; i<25; i++) /*Prints copied strings in specified arrays*/
	{
		for (int j=0; j<78; j++)
		{
			cout << grid[i][j];
		}
		cout << "\n";
	}

it all works, except for the changing of the $, and other symbols' properties. it changes the symbol on the surface, but its properties remains the same as the previous symbol.

You need to use = to change the value of a variable. Have you used = before? You put the variable you want to change on the left, and you put the value you want the variable to have on the right.

i have. i used cout because i thought it worked, but now i find out it only worked superficially. i used

Code:

grid[iy][ix] = '#';

instead and it worked. even though the symbol didn't change, the player cannot pass through the '$' sign now, as though it is actually a '#'. that's nothing a mere cout can't fix! hoho. thanks! this allowed me to proceed with my proj

cout is just a print statement, nothing more.

yeah! i notice it now. tyvm ^_^