comparing user input with a string

Hello again!
Right now I am trying to compare user input with a prepared string. It is not recognizing though.

I have tried these variants:

Code:

getline(cin, input); //input is the string that contains the user input
std::string str2 = "something"; //assume that the user inputs something
if(input==str2)
//does not run

Code:

getline(cin, input); //input is the string that contains the user input
std::string str2 = "something"; //assume that the user inputs something
if(input.compare(str2)==0)
//does not run

Code:

getline(cin, input); //input is the string that contains the user input
//assume that the user inputs something
if(input=="something")
//does not run

Code:

getline(cin, input); //input is the string that contains the user input
//assume that the user inputs something
if(input==(string)"something")
//does not run

Code:

getline(cin, input); //input is the string that contains the user input
//assume that the user inputs something
if(input.compare((string)"something")==0)
//does not run

I do not see how else can this be done.

Are you completely sure that the input string contains exactly "something" .
cout it to verify.

@_@ thanks. I was using a hand-made

Code:

std::string operator&(std::string here)
{
getline(cin, here);
return here;
}

and that was the bugging part. thanks!

Why is that function the address-of operator? It has no reason to be since it's totally unrelated to what the operator does. This is why I dislike operator overloads so much.

Originally Posted by whiteflags

Why is that function the address-of operator? It has no reason to be since it's totally unrelated to what the operator does. This is why I dislike operator overloads so much.

I personally use ~ for output and & for input (because thats what the symbols tell my head @_@ somehow I make connections between the symbols and I/O). I use & for pointers though, if so is needed.

Originally Posted by Shingetsu Kurai

I personally use ~ for output and & for input (because thats what the symbols tell my head @_@ somehow I make connections between the symbols and I/O).

No! That is an abuse of operator overloading. Overload operator<< and operator>> instead because of the strong convention from the standard library (in which case you should also follow the convention for the parameters and return type), otherwise create named functions.