Please explain the following function

[mahor1989]

I have come across a function definition starting as:

int operator*(vector &y)
{
body
}

After putting * just after operator and before opening brace of argument what this function means?

[manasij7479]

It means that :
If you've seen it within a class:
an object of the class when used as : object * somevector ; will yield an integer. Exactly how it'll happen, depends upon the definition..

[King Mir]

And if not within a class, it's unary *, meaning it defines the result of *v, for a vector v.

[manasij7479]

And if not within a class, it's unary *, meaning it defines the result of *v, for a vector v.

Thanks for that info. I did not know that operators could be overloaded in that way..