Reply to CodeMonkey (thread got closed!!!)

This is a discussion on Reply to CodeMonkey (thread got closed!!!) within the C++ Programming forums, part of the General Programming Boards category; CodeMonkey wrote: if 1 = 2 && 2 = 1, what is 3 - (2*2) + 1? Assuming you can ...

  1. #1
    Confused Magos's Avatar
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    Reply to CodeMonkey (thread got closed!!!)

    CodeMonkey wrote:
    if 1 = 2 && 2 = 1,
    what is 3 - (2*2) + 1?
    Assuming you can do what you can't do (changing constant values) this is the answer:

    ¤You set 1 to 2
    ¤You set 2 to 1, but 1=2 so 2 is still 2
    ¤3-(2*2)+1 is 3-(2*2)+2 which is 1

    Answer: 1

  2. #2
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    No, all the 2's change to 1's and the 1's change to 2's
    so the equasion now is:

    3 - (1*1) + 2
    = 3 - 1 + 2
    = 2 + 2
    = 4

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