new way of doing it

Code:

 deduction = 0;
      if(deductiontype.compare("Itemized") == 0)
       {
         while(1)
           {
          input>> deditem;
          if(deditem==0)

         break;
           deduction =deduction+ deditem;
            }
      }

im trying to figure out if there a different way to put while(1)
which equalls true but is there a different way without putting 1 in there

Code:

do{ 
	cin >> ded;
	deduction+=ded;
}while ( ded != 0);

For starters, format your code properly, e.g.,

Code:

deduction = 0;
if (deductiontype.compare("Itemized") == 0)
{
    while (1)
    {
        input >> deditem;
        if (deditem == 0)
            break;
        deduction = deduction + deditem;
    }
}

Now, it is easy to see that you can simplify to:

Code:

deduction = 0;
if (deductiontype.compare("Itemized") == 0)
{
    while ((input >> deditem) && deditem != 0)
    {
        deduction += deditem;
    }
}

Incidentally, if you were just looking to replace the 1, then replace it with true, or you can use for (;;) instead.