Template Argument inside the Argument of a Function Declaration

Take a look at the bold region...It is wrong..but I would need something like that for the constructor..!

Code:

namespace set_mm{
template<class X>
class set
{
    public:
    std::vector<X> dat;
    void insert(X);
    void insert(set<X>);

    set<X>(std::array<X,int>); //haywire...would actually need an int :(
    //Other Constructors
    bool containp(X);  //p for lisp'y predicates..!
    bool subsetp(set<X>);
};
}

The place where I put 'int' must contain a constant integer at compile time...
But.. how would I make the constructor able to handle "std::array"s of many sizes ?.
(I don't need the size to be decided at runtime...the program using the class would have to somehow pass it..)

I am making a set class based on the mathematical concept of set...because std::set is falling short of some of the tasks..and I don't need any sort of searching or sorting ..so vectors instead of a btree.

Try

Code:

   template<int value> set(std::array<X, value>);

(note I haven't tested and am going on memory late at night - it may be necessary to thrown in the typename keyword as well).

Also bear in mind that std::array is not supported in all libraries.

...may be necessary...

Nah..this seems to be working nicely...(though problems may surface when actually implementing the functions after designing the class..).. Thank you very much... (making templates still seem alien to me!)

Code:

std::array is not supported in all libraries

g++ only needed an extra flag for enabling the support for c++0x ...

Yeah, Visual C++ and g++ supports C++11 features, but not all other libraries may.