Large STL String into smaller chunks

Okay, I have tried. I know it is still a little rough, but before I go any farther, anyone know a different or better way?

Code:

#include <string>
#include <vector>
#include <iostream>

using namespace std;

size_t pos;

int main()
{

    string long_string("Hi! I am a string that exceeds twenty characters in length. I need to be cut up into smaller strings");
    vector<string> small_string;
    string string_temp;
    string::iterator it;
    int i;

    while(long_string.length() > 20)
    {
        it = long_string.begin() + 20;
        if(*it != ' ')
        {
            for(i = 19; i > 0; i--)
            {
                it = long_string.begin() + i;
                if(*it == ' ')
                {
                    string_temp.assign(long_string.begin(), it);
                    long_string.erase(long_string.begin(), it);
                    small_string.push_back(string_temp);
                    break;
                }
            }
        }
        else
        {
            string_temp.assign(long_string.begin(), it);
            long_string.erase(long_string.begin(), it);
            small_string.push_back(string_temp);
        }

        if(long_string.length() < 20)
        {
            string_temp.assign(long_string.begin(), long_string.end());
            long_string.erase(long_string.begin(), long_string.end());
            small_string.push_back(string_temp);
            break;
        }
    }

    size_t str_z = small_string.size();

    for(i = 0; i < (int)str_z; i++)
    {
        cout << small_string.at((size_t)i) << endl;
    }
    return 0;
}

I am sure you get the idea. Thanks in advance for any suggestions.

I could read your code and figure out what exactly does it do, but why not just tell us how you intend to split the string into smaller chunks? For example, chunks of a particular maximum size? A specific number of chunks? Chunks split according to certain delimiters found in the string?

I leave it to you to decide whether

Code:

long_string.find_last_of(' ', 20);

meets your needs.

Right you are. Thanks.

What I want to do is find the nearest space to the end of each 20 character long segment of the string and cut the string there, make a new smaller string with that (with a <string>vector.push_back) and then take the next section of 20 characters as from there, and run the same test for the space, until the remaining part of the original string is less than 20 characters long. The last part gets pushed into the last vector.

If that is not very clear, the best I can think of is to say think "word wrap", 20 characters long maximum, in this case.

EDIT:
Thanks, tabstop, was not sure how to use that. Clear(er) now.

Here's what I came up with to cut the line off at 20 chars and store it inside of a string array.

Code:

#include <iostream>
#include <string>
#include <vector>

using namespace std;

int main() {
    string myText("Hi! I am a string that exceeds twenty characters in length. I need to be cut up into smaller strings");

    int countString = 0, startT = 0, stringLen = myText.length();
    vector<string> tmpStor(10);

    while ( (startT + 20) < stringLen ) {
        tmpStor[countString] = myText.substr(startT,20);
        cout << tmpStor[countString] << endl;
        countString++;
        startT += 20;
    }
    tmpStor[countString] = myText.substr(startT);

    //Complete Line
    int i = 0;
    while (tmpStor[i].length() > 0) {
        cout << tmpStor[i];
        i++;
    }

    return 0;
}

Just realized you probably don't want to cut words off ... how bout this.

Code:

#include <iostream>
#include <string>
#include <vector>

using namespace std;

int main() {
    string myText("Hi! I am a string that exceeds twenty characters in length. I need to be cut up into smaller strings");

    int countString = 0, startT = 0, stringLen = myText.length();
    vector<string> tmpStor(10);

    while ( (startT + 20) < stringLen ) {
        int tmpStr;
        tmpStor[countString] = myText.substr(startT, 20);
        tmpStr = tmpStor[countString].find_last_of(' ', (startT + 20));
        if ( tmpStr < 19 ) {
            tmpStor[countString] = myText.substr(startT, tmpStr);
            startT += tmpStr;
        } else {
            startT +=  20;
        }
        cout << tmpStor[countString] << endl;
        countString++;
    }
    tmpStor[countString] = myText.substr(startT);
    //Complete Line
    int i = 0;
    while (tmpStor[i].length() > 0) {
        cout << tmpStor[i];
        i++;
    }

    return 0;
}

I have already managed to figure out something along those lines, xentaka, but thank you very much for the suggestion just the same!

Consider this one solved, thanks again, and all the best.

For posterity and reference... (I have a poor memory)

Code:

#include <string>
#include <vector>
#include <iostream>

using namespace std;

int main()
{

    string long_string("Hi! I am a string that exceeds twenty characters in length. I need to be cut up into smaller strings");
    vector<string> small_string;
    string string_temp;
    //string::iterator it;
    size_t i;
    size_t marker_1 = 0, marker_2 = 0;

    while((marker_1 + 20) < long_string.length())
    {
        marker_2 = long_string.find_last_of(' ', (marker_1 + 20));
        string_temp.assign(long_string.begin() + marker_1, long_string.begin() + marker_2);
        if(*string_temp.begin() == ' ')
            string_temp.erase(string_temp.begin());

        small_string.push_back(string_temp);
        marker_1 = marker_2;
    }
    if((long_string.length() - marker_1) > 0)
    {
        string_temp.assign(long_string.begin() + marker_1, long_string.end());
        if(*string_temp.begin() == ' ')
            string_temp.erase(string_temp.begin());

        small_string.push_back(string_temp);
    }

    size_t sl_z = small_string.size();

    for(i = 0; i < sl_z; i++)
    {
        cout << small_string.at(i) << endl;
    }
    return 0;
}