In the QT4 documentations, I'm frequently seeing statements like..
I am assuming that menuBar() returns a pointer to an object..(Does it?)Code:fileMenu = menuBar()->addMenu(tr("&File"));
What happens after that ..is not comprehensible by me.
Any simple explanation ?
It's like this, without the extra variables
Code:currentMenuBar = menuBar(); fileMenu = currentMenuBar->addMenu(tr("&File"));
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
...now I see...
and then
returns something, which becomes the rvalue ...Code:addMenu(tr("&File"));
Sure, tr() returns something that addMenu() will accept as a parameter, and it returns a fileMenu value.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
