help with code problem

When I run this code I get an error saying that the function int DiceNum(int) has too few arguments. Does anyone have any ideas? And also can anyone tell me how to loop the game to restart at the end if the user chooses?

Code:

#include <iostream>
#include <cstdlib>
#include <ctime>

using namespace std;

int randGen(int x);                 //function for generating random on die
int DiceNum(int num);               //function for the 6 different dice rolls

    short int diNumI;               //dice number bet on
    int moneyO = 0;                 //points record variable
    unsigned int moneyB;            //money places in bet

int main()
{
    cout << "Place a bet 5, 10, 25, or 100: ";

    unsigned short int dNum;            //dice number choice input by the player (variable statement)

    cin >> moneyB;

    switch(moneyB)
    {
        case 5:
            cout << "What number will the die land on? \n";
            cin >> diNumI;
            cout << "Push Enter to roll die. \n";
            DiceNum();
            break;

        case 10:
            cout << "What number will the die land on? \n";
            cin >> diNumI;
            cout << "Push Enter to roll die. \n";
            DiceNum();
            break;

    }

    return 0;
    cin.get();
}



int randGen(int x){          //random generator function

    srand(time(0));
    x = 1+(rand()%6);
    cout << 1+(rand()%6);
    return x;
}

int DiceNum(int num){

    char Lchoice[3];        //choice to play again

    num = randGen();

    if(diNumI == num){      //if die number guess is correct
        cout << "You won! \n";
        moneyO = moneyO + moneyB;
        sleep(1000);
        cout << "Try again?"
        cin >> Lchoice;
            if(Lchoice == 'yes'){
                //restart
            }
            else if(Lchoice == 'no'){
            return 0;
            }
    }

    else if(diNumI !== num){
        cout << "No the number was ";
        cout << num;
        cout << "Try again?\n";
        cin >> Lchoice;

             if(Lchoice == 'yes'){
                //restart
                return 1;
            }
            else if(Lchoice == 'no'){
            return 0;
            }
    }
}

Originally Posted by Jayb

When I run this code I get an error saying that the function int DiceNum(int) has too few arguments. Does anyone have any ideas?

Yes: when you call DiceNum, provide an argument. That is, this is wrong:

Code:

DiceNum();

Your compiler's error message should have included a line number telling you as such.

Oh wow I feel stupid. Thanks. It didn't have a marker showing me this line that's why I didn't notice it right away. Do you know how to loop this to where if they choose to play again it loops?

@Jayb - even without showing you the line - the compiler told you exactly and word by word what was wrong. Sometimes it's a bit more difficult to make sense out of compiler messages; but still, *reading* them is always the first thing to do. (No offense here, just a hint.)

Error messages can be difficult to understand for those without experience. Those new to a programming language will almost certainly have trouble interpreting error messages. Then there's the problem of switching between compilers...

Originally Posted by Elysia

Error messages can be difficult to understand for those without experience. Those new to a programming language will almost certainly have trouble interpreting error messages. Then there's the problem of switching between compilers...

Sure, no argument here. I spotted that too. Nevertheless, reading the messages is a good thing to do. First of all, as you make your progress, you will gain understanding of those messages bit by bit, and secondly, in this special case, the message told Jayb exactly and without any need for interpretation what the problem was.