Using do while to print # of words per line...

Hi, I can make do while loop to work here. It is suppost to print user defined(numPerLine) words per line but for some reason it prints all in one line. I know something is wrong with my do while. Didn't practice do while enough and now i am having trouble (I like fro loop )

Code:

#include <iostream>
#include <iomanip>

using namespace std;

//function prototypes

int getNumber();
int printnumPerLine();
void printResult(int, int);

int main()
{
int num;
int numPerLine;

num = getNumber();
numPerLine = printnumPerLine();
printResult(num, numPerLine);
}

//get input from keyboard and return it to caller
int getNumber()
{
int num;
	cout << "\n\nPlease enter a non-negative number: ";
	cin >> num;
	
	return num;
}

int printnumPerLine()
{
	int numPerLine;

	cout << "\nHow many numbers per line? ";
	cin >> numPerLine;

	return numPerLine;
}
//print our result
void printResult(int num, int numPerLine)
{
	int i = 0;

	do{
		cout << setw(4) << i;
		i++;
	} while (i<=num);
		
	if(i % numPerLine == 0){
			cout << endl;
	}
	cout << endl << endl;
}

Thanks

sorry, I had to post it again because I unintentionally posted it to C forums instead.

Untill you pass 'cout' a newline character '\n' or 'endl', it will keep printing on the same line.

Where do I need to enter endl?

I did it here:

Code:

if(i % numPerLine == 0){
	cout << endl;

Thanks

Originally Posted by Iron Hide

Where do I need to enter endl?

I did it here:

Code:

if(i % numPerLine == 0){
	cout << endl;

Thanks

You've already printed all the numbers by the time you get there, since that is after your loop. Perhaps you intended to place it inside the loop?

works! I tried pacing it various paces but this one Thanks