Char[1024] to char

I have written the following code (names file is fine and that is not the issue. It is the old chesnut of converting char, char*, string arrays.

Code:

#include <iostream>

using namespace std;

int main()
{
	FILE *txtfile;
	char line[1024];
	char studentlist[6];
	int pos=0;

	if((txtfile=fopen("Names.DAT","r"))==NULL)
		exit(-1);

	cout << "The names in the text file are:" << endl;
	cout << endl;

	while(fgets(line,1024,txtfile)!=NULL)
		
		//cout << line;
		studentlist[0]=line;
		cout << studentlist[0];

	fclose(txtfile);
	cin.get();
}

So why not go all the way to C++, use C++ streams, and use C++ std::string to store the information you read.

Originally Posted by musicman

I have written the following code (names file is fine and that is not the issue. It is the old chesnut of converting char, char*, string arrays.

Code:

#include <iostream>

using namespace std;

int main()
{
	FILE *txtfile;
	char line[1024];
	char studentlist[6];
	int pos=0;

	if((txtfile=fopen("Names.DAT","r"))==NULL)
		exit(-1);

	cout << "The names in the text file are:" << endl;
	cout << endl;

	while(fgets(line,1024,txtfile)!=NULL)
		
		//cout << line;
		studentlist[0]=line;
		cout << studentlist[0];

	fclose(txtfile);
	cin.get();
}

The line marked in red is assigning a char * to a char. This will get you a compile time error.

You should, like Salem said, use C++ streams and std::string for the studentlist.