Thread: Question about Boolean expression

!( 1 || 1 && 0 ) ANSWER: 0 (AND is evaluated before OR)

The above is from the C++ tutorial. The tutorial gives the answer as 0 (or false) with the explanation, (AND is evaluated before OR).

My question is: if 1 && 0 is 0 (or false) doesn't the ! outside the parentheses convert the final result to !0 ( 1 or true)?

Thank you.

Never mind. I see what I did what.

B. !( 1 || 1 && 0 ) ANSWER: 0 (AND is evaluated before OR)

1 && 0 is evaluated first and results in 0

then you evaluate:

1 || 0

which results in 1 (or True)

but then the ! negates 1 to !1 or 0 (false).

Does everyone else have a headache now? :-)

Originally Posted by hk_mp5kpdw

1 || 0 = 1
!1 = 0

Thanks for your reply.