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Question about Boolean expression

This is a discussion on Question about Boolean expression within the C++ Programming forums, part of the General Programming Boards category; !( 1 || 1 && 0 ) ANSWER: 0 (AND is evaluated before OR) The above is from the C++ ...

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    Question about Boolean expression

    !( 1 || 1 && 0 ) ANSWER: 0 (AND is evaluated before OR)

    The above is from the C++ tutorial. The tutorial gives the answer as 0 (or false) with the explanation, (AND is evaluated before OR).

    My question is: if 1 && 0 is 0 (or false) doesn't the ! outside the parentheses convert the final result to !0 ( 1 or true)?

    Thank you.

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    1 || 0 = 1
    !1 = 0
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    Never mind. I see what I did what.

    B. !( 1 || 1 && 0 ) ANSWER: 0 (AND is evaluated before OR)

    1 && 0 is evaluated first and results in 0

    then you evaluate:

    1 || 0

    which results in 1 (or True)

    but then the ! negates 1 to !1 or 0 (false).

    Does everyone else have a headache now? :-)

    Quote Originally Posted by hk_mp5kpdw View Post
    1 || 0 = 1
    !1 = 0
    Thanks for your reply.

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    Just the matter of precedence and evaluation that a normal person mostly misinterprets...
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