Help with syntax error (constructor)

[843]

student::student(string name,float g)
{
	cout <<"student constructor is running..." <<endl;
    student.sname=name; //problem line
	gpa=g;
}

For some reason, I keep getting error C2143: syntax error : missing ';' before '.'

Here's the full code:

#include <iostream>
#include <string>
using namespace std;

class student
{
public:
    string sname;
    float gpa;

    student(string name);
	student(string name,float g);
	~student();
    void display();
private:
	string name;
    float g;
};

student::student(string name,float g)
{
	cout <<"student constructor is running..." <<endl;
    student.sname=name;
	gpa=g;
}

student::student(string name)
{
	cout <<"student constructor is running..." <<endl;
    student.sname=name;
	gpa = 0.0;
}

student::~student()
{
	//cout <<"Student No.: "<<i<<endl; (Is there any way to use a variable as argument here?)
	cout <<"student destructor is running..." <<endl;
}

void student::display()
{
	string sname;
	float gpa;

	cout <<"Student Name:" <<sname <<endl; //sname private
	cout <<"Student GPA:" <<gpa <<endl; //gpa private
}

[Salem]

Remove the student. from in front of the member variable names.

And no, the destructor does NOT have parameters. It destroys exactly ONE instance at a time.
If you've got many instances of an object, you'll get that many calls at some point.

[843]

Thanks, Salem! There is still the problem of using input parameters in destructor. Is it possible?

[Salem]

See reply ^^

[Elysia]

Thanks, Salem! There is still the problem of using input parameters in destructor. Is it possible?

No, because a destructor is called by the compiler, and its only purpose is to destroy its own instance.
However, the destructor can naturally access all of its instances member variables. So when you create an instance, you can assign it an identifier or name. You can then print out this in the destructor.
You could also print "this", since every instance must have a unique memory address.