My first time posting. This program is/was a homework problem. It works as required, but I would like to eliminate negative numbers and have it exit with the input of a negative rather than zero. All mods i have made just screwed it up and I know it's simple. What areas need to be changed to get this ?
Code:#include <iostream> #include <iomanip> #include <string> #include <cmath> using namespace std; class Numbers { private: int number; public: Numbers(int a) {number=a;} void print(); }; void Numbers::print() { int n; string lessthan20[20]={"zero","one","two","three","four","five","six","seven", "eight","nine","ten","eleven","twelve","thirteen", "fourteen","fifteen","sixteen","seventeen", "eighteen","nineteen"}; string tens[10]={"zero","ten","twenty","thirty","forty","fifty","sixty", "seventy", "eighty", "ninety"}; if(number<0) cout<<"negative "; number=abs(number); n=number/1000; if(n>0) cout<<" "<<lessthan20[n]<<" thousand "; number%=1000; n=number/100; if(n>0) cout<< lessthan20[n]<<" hundred "; number%=100; if(number>=20) { n=number/10; if(n>0) cout<<tens[n]<<" "; } else if(number>=10) { cout<< lessthan20[number]<<" "; return; } number%=10; if(number>0) cout<<lessthan20[number]; cout<<" "; } int main() { int n; cout<<" This program will take an input of up to four(4) numerals\n"; cout<<" and change them to a written number.\n"; cout<<" Enter up to a four-digit number(0 to exit): "; cin>>n; while(n!=0) { Numbers number(n); number.print(); cout<<"\nEnter a number(0 to exit): "; cin>>n; } system("pause"); return 0; }



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