Change maker program remainder troubles.

I have to make a program into which the user enters their bill in a decimal number and the remainder is broken down into dollars, quarters, dimes, nickels and pennies. I learned how to use setprecision(x). Here's my code:

Code:

#include <iostream>
#include <iomanip>
using namespace std;

int main() {
    double bill, paid, dollars, quarters, dimes, nickels, pennies, remaindol = (paid - bill);
    cout << "Welcome to my change-maker program! " << endl;
    cout << "To begin, press ENTER. " << endl;
    getchar();
    
    restart:
    
    cout << "\n\nEnter how much the bill is. " << endl;
    cout << "Do not use a $ sign. Just enter the decimal number. " << endl;
    cin >> bill;
    cout << "Now enter how much cash you paid. " << endl;
    cin >> paid;
    if (paid < bill) {
             cout << "Uh-oh! You need to pay more cash. You " << endl;
             cout << "haven't paid the whole bill yet. " << endl;
             cout << "You still owe " << setprecision(2) << fixed << (bill - paid) << ". " << endl;
             goto restart;
             }
    
    if (bill <= paid) {
             cout << "You should get " << (paid - bill) << " in change. " << endl;
             cout << "The most efficient way to get your " << (paid - bill) << " would " << endl;
             cout << "be to get: " << endl;
             //need to fit in change. narrow down.
}

getchar();
return (0);
}

How do I use % to narrow it down? I'm stuck. :[

The modulus operator (%) will not work with floating point numbers, so you will have to convert your floating point numbers to an int.


Jim

fmod - C++ Reference

Sorry, I yet again double posted a new thread.
A more detailed one is HERE, mods can close this one (thanks for the help btw).