And if the reverse is true?

And how would we code "then I would compare the numbers from the next pair to the 1st pair and see which one is the biggest and smallest"?

This is a discussion on *Extracting and comparing numbers* within the **C++ Programming** forums, part of the General Programming Boards category; And if the reverse is true?
And how would we code "then I would compare the numbers from the next ...

- 03-01-2011 #31

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- 03-01-2011 #32

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Code:if( current1 > current2 ){ largeNum = current1; smallNum = current2; } if( current2 > current1 ){ largeNum = current2; smallNum = current1; }

- 03-01-2011 #33

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- 03-01-2011 #34

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It was stored into largeNum and smallNum... Ohh, so do I compare smallNum and largeNum to current1 and current2?

- 03-01-2011 #35

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Exactly. So we're almost done.

We have two cases... the first pass and the nth pass.

Can you puzzle them together? It's possible.

Hint: SmallNum and BigNum must of course be initialized before we can compare to them. So what should they be initialized to?

- 03-01-2011 #36

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largeNum should be initialized to 0 and smallNum to 9... but why would we need to initialize them if we are making them current1 and current2 from this first pair?

- 03-01-2011 #37

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Well, we have two cases.

In the first iteration, we want to compare current1 to current2 and assign BigNum from the biggest of current1 or current2.

In the nth iteration, we want to compare BigNum to current1 and current2 and assign BigNum to current1 or current2, if any if bigger than BigNum.

You could code both cases. Or you could integrate them into one case if you want. It just requires some thinking. Either way, it's up to you.

- 03-01-2011 #38

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Ok, so with

Code:if( current1 > largeNum ){ largeNum = current1; } if( current2 > largeNum ){ largeNum = current2; }

- 03-01-2011 #39

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- 03-01-2011 #40

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Ok, I figured it out for the most part :

Code:while (num != 0){ current1 = num % 10; num /= 10; cout <<"curr:" << current1 << endl; if( current1 > largeNum ){ largeNum = current1; } if( current1 < smallNum ){ smallNum = current1; } }

- 03-01-2011 #41

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- 03-01-2011 #42

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How about this?

Code:if( num != 0 ){ while (num != 0){ current1 = num % 10; num /= 10; cout <<"curr:" << current1 << endl; if( current1 > largeNum ){ largeNum = current1; } if( current1 < smallNum ){ smallNum = current1; } } } else{ largeNum = 0; smallNum = 0; }

- 03-01-2011 #43

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- 03-01-2011 #44

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Also, if you don't mind, can you help me with one more thing? In this code I also need to find out how to find the total of all numbers extracted from 'num'.

- 03-01-2011 #45

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