error: invalid conversion from 'int' to 'int*'

This is a discussion on error: invalid conversion from 'int' to 'int*' within the C++ Programming forums, part of the General Programming Boards category; Hi everyone, on line 76 I get the error of an invalid conversion from and int to *int. Please bear ...

  1. #1
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    error: invalid conversion from 'int' to 'int*'

    Hi everyone, on line 76 I get the error of an invalid conversion from and int to *int. Please bear in mind the function prototype for findmax must be the way it is. Can anyone help me? I appreciate it.
    Code:
    #include <iomanip>
    #include <iostream>
    
    using namespace std;
    
    #define MAX 100
    
    bool isAscending (int *a, int len);
    bool isDescending (int *a, int len);
    bool isInOrder (int *a, int len);
    double avg (const int *x, int len);
    int *findmax (const int *x, int n);
    int getInfo (int *a, int max);
    int total (const int *a, int len);
    void sort (int *x, int n);
    void swap (int &x, int &y);
    
    int main()
    {
        int a[MAX];
        int i = 0;
        int len;
        len = getInfo (a, MAX);
        double x = avg (a, len);
    
        if (len > 0) cout << "Avg: " << x << endl;
        for (;i < len; i++) cout << setw(4) << *(a+i);
        cout << endl;
    
        if (isInOrder(a, len)) cout << "its in order" << endl;
        else sort(a, len);
    
        if (isInOrder(a, len)) cout << "its in order" << endl;
    
        for (i = 0; i < len; i++) cout << setw(4) << *(a+i);
        cout << endl;
    
        return 0;
    }
    
    bool isAscending (int *a, int len)
    {
        for (int i = 0; i < len - 1; i++)
            if (*(a+i) > *(a+i+1)) return false;
        return true;
    }
    
    bool isDescending (int *a, int len)
    {
        for (int i = 0; i < len - 1; i++)
            if (*(a+i) < *(a+i+1)) return false;
        return true;
    }
    
    bool isInOrder (int *a, int len)
    {
        return isAscending(a, len) || isDescending(a, len);
    }
    
    double avg(const int * a, int len)
    {
        int tot = total(a,len);
        return (double)tot / len;
    }
    
    
    int *findmax(const int *x, int n)
    {
        int temp = 0;
        int i = 1;
        while (i <= n)
        {
            if (*(x + i) > *(x + temp)) temp = i;
            i++;
        }
        return temp;
    }
    
    int getInfo(int *a, int max)
    {
        int i = 0;
        while (cin >> *a)
        {
            a++;
            i++;
            if (i == max) break;
        }
        return i;
    }
    
    int total (const int *a, int len)
    {
        int sum = 0;
        while (len--) sum +=*a;
        return sum;
    }
    
    void sort (int *x, int n)
    {
        int j;
        while (n--)
        {
            j = *findmax(x, n);
            swap (*(x + j), *(x + n));
        }
    }
    
    void swap(int &x,int &y){
    int temp = x;
    x = y;
    y = temp;
    }
    Oh sorry! Line 76 is;
    Code:
    return temp;

  2. #2
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    You are supposed to return an integer pointer, not an int. According to my understanding of the meaning of this function, just return (x+temp).

  3. #3
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    I do not think that is it. It gives me the same error only now it says "const int* to int*" for the same line. The prototype for the function must be intact. If I remove the * in the function prototype the program works perfectly but unfortunately I have to use the *.

  4. #4
    Algorithm Dissector iMalc's Avatar
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    x+temp is correct except that it will also require a const_cast to remove the constness.

    The method signature is a bit dubious though, due to the const in only one of the two places.
    My homepage
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  5. #5
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    Thanks everyone! It is now working!

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