user defined class with overloaded insertion and stream extraction ?

[sharris]

This code is using string. How do I change the data type to integer and obtain the same type of results or near. If shown to me I'm sure I can complete the next three required steps.

Thanks in advance

#include <iostream>
#include <iomanip>
#include <string>
using namespace std;

class POINT
{
friend ostream &operator<<( ostream &, const POINT & );
friend istream &operator>>( istream &, POINT & );
private:
string xCoordinate; // 3-digit
string yCoordinate; }; // 4-digit




ostream &operator<<( ostream &output, const POINT &var )
{
output << var.xCoordinate << "." << var.yCoordinate;
return output; }




istream &operator>>( istream &input, POINT &var )
{
input >> setw( 3 ) >> var.xCoordinate; // input x
input.ignore(); // skip period (.)
input >> setw( 4 ) >> var.yCoordinate; // input y
return input; // cin >> x >> y;
}





int main()
{
POINT point;

cout << "Enter point in the form 456.7890:" << endl;
cin >> point;

cout << "The number entered was: ";
cout << point << endl;

system("pause");
system ("CLS");

}

[tabstop]

If you change the data type of the member variables to int (from string), I don't actually see anything that needs to change much. If you want to print things as 037.0009, then you'll have to look in <iomanip> for the flag to left-fill with zeroes

[sharris]

Ooooo Thank you tabstop. I was not sure if I even had it had it half way right though it was looking good to me. Now I see I needed to add some of the other I/O manipulators to get this code going before moving into the fun stuff that I do have a clue about.

I just now included this:

cout << setw(3) << setfill('0') << point << '\n';

And now I can type 123.1234 and it will output 123.1234 ... but before (type as string) I did not have to type the period. It would pop in automatically. I guest I'll figure out why latter but for now WOW! And to think I was about to change everything and loss it all and not recover. I almost lost faith. Thanks again