Explicit specialisation of function template as member of class template

[MarkZWEERS]

Hi,

How on earth do I explicitely specialize :

template<typename U>
class A {
public:
  template<typename T> void f(T& v)
  {
    // do something in general with u_
  }
  U u_;
};

this doesn't work :

template<>
void A<int> :: f<double> (double& v) {
// do something special with int
}

Thanks !!

[tabstop]

Shouldn't the T match the "int"?

[MarkZWEERS]

Nope, T should match double'. But you're right, i forgot to specialize f's parameter.

I've corrected my post, but it doesn't compile. g++ sais :

new.cpp:67: error: template-id ‘f<double>’ for ‘void A<int>::f(double&)’ does not match any template declaration

[MarkZWEERS]

eureka !

First I need to indicate an explicit specialization for the class, then for the function. This works :

template<>
template<>           /// < ---
void A<int> :: f<double> (double& v) {
// do something special with int
}