Thread: Problem with abs(double)

It's very basic but I have problem getting the absolute value of a double type; here:

Code:

double *Dist_cb1= new double[2400];
for (i=0; i<2400; i++){
		Dist_cb1[i]=0;
		for (j=0; j<6; j++)
			
			Dist_cb1[i] = Dist_cb1[i] + abs(abs(Dataf[j] - train1[i][j])); printf("%f        ", Dist_cb1[i]);
			
	}

when I try to get the absolute value of the subtraction of two doubles I receive a large value which should be an address.

I don't know if you're doing it deliberately, but putting that printf statement on the same line as the assignment to Dist_cb1[i] would lead people to think that it will happen every time through the loop, when it won't.

There's no point in doing abs() twice I wouldn't think either. Note that abs is overloaded to work with floats and doubles and things if you use std::abs instead of just abs.