Menu Numbering Problem

The only problem I am running into when I run this program is that fact that my 2nd for loop doesn't print out 1,2,3 just 0,1,2. I understand why it prints out the second type but how do I fix it ? My first thought was to replace it with for(int i=1;i<3;++i) but that will skip my 0 position element all together or give me a run-time error

If anyone can help me solve this problem It would be very helpful.

Code:

#include <iostream>
#include<vector>
#include<string>

using namespace std;

int main()
{

   string game0,game1,game2;

   vector<string>myGames;
   vector<string>::iterator iter;

   cout<<"What is Your Favorite Game :";
   cin>>game0;
   cout<<"What is Your 2nd Favorite Game :";
   cin>>game1;
   cout<<"What is Your 3rd Favorite Game : ";
   cin>>game2;


   myGames.push_back(game0);
   myGames.push_back(game1);
   myGames.push_back(game2);

    cout<<"\n\t\tTop 3 Favorite Games\n";

    for( iter=myGames.begin(); iter!=myGames.end();++iter)
            cout<<". "<<*iter<<endl;

    int choice;
    char replace;
    cout<<"\nDo you want to replace a game (y/n) :";
    cin>>replace;

while (replace=='y')
{
   for(int i = 0; i<myGames.size();++i)
        cout<<i<<". "<<myGames[i]<<endl;

    cout<<"\nWhat is Your Choice :";
    cin>>choice;

    switch (choice)
{

    case 1:                         myGames.erase(myGames.begin());
                                        cout<<"\nWhat's Your New #1 Game ? ";
                                        cin>>game0;
                                        myGames.insert(myGames.begin(),game0);
                                        break;

    case 2:                        myGames.erase(myGames.begin()+1);
                                        cout<<"\nWhat's Your New #2 Game ? ";
                                        cin>>game1;
                                        myGames.insert(myGames.begin()+1,game1);
                                        break;

    case 3:                        myGames.erase(myGames.begin()+2);
                                        cout<<"\nWhat's Your New #3 Game ? ";
                                        cin>>game2;
                                        myGames.insert(myGames.begin()+2,game2);
                                        break;
    default:            cout<<"Wrong Number Try Again\n";
                                        continue;
}

    cout<<"\nDo you want to replace another (y/n) :" ;
    cin>>replace;
    cout<<"\n";
}
    cout<<"\n\t***Top 3 Favorite Games***\n";
      for(int i = 0; i<myGames.size();++i)
        cout<<i<<". "<<myGames[i]<<endl;


    return 0;
}

So don't print i; print i+1 instead.

LOL didn't even know you could do that

Using this code: (int i=1;i<3;i++) will not produce the number 3 ever, because your control statment runs the loop only when 'i' is LESS than 3. If you want to produce 3, your code should look like:

(int i=1;i<=3;i++)