Populate An Array With Numbers

This is a discussion on Populate An Array With Numbers within the C++ Programming forums, part of the General Programming Boards category; I am having problems with populating an array with int numbers. Since I am a new programmer, I do not ...

  1. #1
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    Populate An Array With Numbers

    I am having problems with populating an array with int numbers. Since I am a new programmer, I do not know why my VS 2008 is not completing the code block. In other words when I execute the program, a blank console screen opens. I then input a number and press enter. After I press enter the program stops in a suspended state. What I have discovered is that I have to input a \o for the program to know that it is the end of my input. I though thought that when I pressed enter, VS 2008 would automatically place this end of string designator.

    Secondly, I have problems with index variable. When I loop one time or when I press enter after inputing a number, my index number advances to 8. My question is why the index does not advance to 2?

    Code:
    #include <stdio.h>
    
    int const limit = 8;
    int numbers[limit];
    int main(void)	
    {	
         for(int index = 0; index < limit; index++)		
         {		
         scanf("%d", &numbers[limit]);
         }
    return 0;
    }
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  2. #2
    and the Hat of Guessing tabstop's Avatar
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    You have to type eight numbers, not one number.

    Also note that you are throwing (all of) the numbers away, since you do not store the input in a valid memory location.

  3. #3
    -bleh-
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    Code:
    scanf("%d", &numbers[index]);
    Last edited by nimitzhunter; 01-08-2011 at 01:57 AM.
    "All that we see or seem
    Is but a dream within a dream." - Poe

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    nimitzhunter and tabstop,

    Thank you both for your reply.

    What I have learned is that first off, the input into the console screen needs to be a number and a space. When the numbers to be stored is less than the total array elements, a \o can be used to end the input and not fully populate the complete array.

    Apparently, when only one element is input into an array with 8 elements, the for statement advances the index to the total of the array elements (ie. 8 total elements) when the enter key is pressed after entering only one element.

  5. #5
    and the Hat of Guessing tabstop's Avatar
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    Quote Originally Posted by mcertini View Post
    nimitzhunter and tabstop,

    Thank you both for your reply.

    What I have learned is that first off, the input into the console screen needs to be a number and a space. When the numbers to be stored is less than the total array elements, a \o can be used to end the input and not fully populate the complete array.

    Apparently, when only one element is input into an array with 8 elements, the for statement advances the index to the total of the array elements (ie. 8 total elements) when the enter key is pressed after entering only one element.
    None of your last paragraph is true, and I'm not even sure what you mean by the second paragraph, as it is not possible to type an end-of-string character '\0' at the keyboard at all.

    If you mean that you literally typed \o, as in the character backslash and the character o, then what happened is that each of your input statements failed, since \ is not a digit, meaning the value of numbers[limit] (if it existed, which it doesn't) wasn't changed.

  6. #6
    and the Hat of Guessing tabstop's Avatar
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    That is to say, this is what is supposed to happen (you type eight numbers, and they get added to the array (assuming you made the limit->index fix as pointed out above):
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