hwhere to put the msg in Fabonacci series

This is a discussion on hwhere to put the msg in Fabonacci series within the C++ Programming forums, part of the General Programming Boards category; Hi friends I am having trouble putting the "not a fabonacci number" msg in my code , plz help /* ...

  1. #1
    Registered User
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    Dec 2010
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    hwhere to put the msg in Fabonacci series

    Hi friends

    I am having trouble putting the "not a fabonacci number" msg in my code

    , plz help


    /*
    Name: fabonacci series and searching of element
    Copyright: devesh
    Author:
    Date: 14/12/10 01:29
    Description:
    */
    14/12/10 01:29
    #include<iostream.h>
    #include<conio.h>

    int main()


    {
    int fab,x1=0,x2=1,no,a[18];

    for(int i=0;i<18;i++)
    {
    fab=x2+x1;
    x1=x2;
    x2=fab;
    a[i]=fab;
    cout<<fab<<" ";
    }


    cout<<"\n\n enter the no to test :";
    cin>>no;

    for(int j=0;j<18;j++)

    {
    if(a[j]==no )
    {
    cout<<"\n\n Fabonacci";
    break;
    }
    }
    getch();
    }

  2. #2
    -bleh-
    Join Date
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    Quote Originally Posted by deva View Post
    Hi friends

    I am having trouble putting the "not a fabonacci number" msg in my code

    , plz help

    Code:
    /*
      Name: fabonacci series and searching of element
      Copyright: devesh
      Author: 
      Date: 14/12/10 01:29
      Description: 
    */
    14/12/10 01:29
    #include<iostream.h>
    #include<conio.h>
    
    int main()
    
    
    {
        int fab,x1=0,x2=1,no,a[18]; 
        
        for(int i=0;i<18;i++)
        {
        fab=x2+x1;
        x1=x2;
        x2=fab;
        a[i]=fab;
        cout<<fab<<"  ";
        }
        
        
        cout<<"\n\n enter the no to test :";
        cin>>no;
        
        for(int j=0;j<18;j++)
        
        {
        if(a[j]==no )
        {
        cout<<"\n\n Fabonacci";
        break;     
        }
        }
        getch();
    }
    you can't really do that in the for loop. How about checking for true or false in the for loop and then write the statement outside.

    Code:
    bool fib = false;
    for(int j=0;j<18;j++)
    {
      if(a[j]==no )
         {
           fib = true;
           break;     
        }
    }
    if ( fib == true)
       std::cout << no << " is a fib" << std::endl;
    else
      std::cout << no << " is not a fib << std::endl;
    "All that we see or seem
    Is but a dream within a dream." - Poe

  3. #3
    and the hat of wrongness Salem's Avatar
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