replacing charcters for other characters

hey, im a bit stuck with this programming assignment ive been playing around with

i basically have to take a word ( or serval words) and code them

with an offset provided by the user so

a=b is the 1st offset
a=c is the 2nd offset

and so on

ive written this as a test , but it doesnt print the final word

any help???

++++++++++++
(btw... i know i havent covered all the possiblitties but this is just a test)++++++++++



************************************************** *******
insert

Code:

#include<stdio.h>
#include <string.h>

#define size 3

int  main (void)

{
		
	char name[]= "aaa";		// setting name input
	char new_name[size];	               // setting name output
		
	int pointer                                                //counter variable
	int offset;				// setting variable for offset 

	printf(" please enter in a offset" );
	scanf("%d", &offset);
	
	switch (offset)

	{
		case 1:						
//************* giving an offset of 1

	for (pointer=0; pointer<=size ; pointer++)																			pointer = 0;

		{	if (name[pointer] = 'a')
				new_name[pointer] = 'b';

			else if (name[pointer] ='b')
				new_name[pointer] = 'c';

			else if (name[pointer] = 'c')
				new_name[pointer] = 'd';

			else (name[pointer] = 'd');
				new_name[pointer] = 'e';
		}			
			
		printf(" the coding is %d", new_name);

	break;



		case 2:	
	//**********giving an offset of 2

	for (pointer=0; pointer<=size ; pointer++)																								// sum = the equation
	pointer = 0;

		{	if (name[pointer] = 'a')
				new_name[pointer] = 'c';

			else if (name[pointer] ='b')
				new_name[pointer] = 'd';

			else if (name[pointer] = 'c')
				new_name[pointer] = 'e';

			else (name[pointer] = 'd');
				new_name[pointer] = 'f';
		}			
			
		printf(" the coding is %d", new_name);
			 
	break;

		case 3:						
//************** giving an offset of 3

	for (pointer=0; pointer<=size ; pointer++)																								// sum = the equation
	pointer = 0;

		{	if (name[pointer] = 'a')
				new_name[pointer] = 'd';

			else if (name[pointer] ='b')
				new_name[pointer] = 'e';

			else if (name[pointer] = 'c')
				new_name[pointer] = 'f';

			else (name[pointer] = 'd');
				new_name[pointer] = 'g';
		}			
			
		printf(" the coding is %d", new_name);
			 
	break;
			default:
			printf(" non valid offset") ;
	}
}

First, enable some warnings in your compiler, so you can catch more problems before you run.

Code:

$ gcc -Wall foo.c
foo.c: In function ‘main’:
foo.c:27: warning: suggest parentheses around assignment used as truth value
foo.c:30: warning: suggest parentheses around assignment used as truth value
foo.c:33: warning: suggest parentheses around assignment used as truth value
foo.c:40: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘char *’
foo.c:52: warning: suggest parentheses around assignment used as truth value
foo.c:55: warning: suggest parentheses around assignment used as truth value
foo.c:58: warning: suggest parentheses around assignment used as truth value
foo.c:65: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘char *’
foo.c:75: warning: suggest parentheses around assignment used as truth value
foo.c:78: warning: suggest parentheses around assignment used as truth value
foo.c:81: warning: suggest parentheses around assignment used as truth value
foo.c:88: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘char *’
foo.c:94: warning: control reaches end of non-void function

In particular, make sure case 1: works before copy/pasting mistakes into case 2 and case 3
- You're using = where you should be using ==
- You're using %d to print a string.

> for (pointer=0; pointer<=size ; pointer++) pointer = 0;

Does your editor have horizontal scroll bars?
Because there is a bit of bad news stuck far to the right on this line.

Is this C or C++?