replacing charcters for other characters

This is a discussion on replacing charcters for other characters within the C++ Programming forums, part of the General Programming Boards category; hey, im a bit stuck with this programming assignment ive been playing around with i basically have to take a ...

  1. #1
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    replacing charcters for other characters

    hey, im a bit stuck with this programming assignment ive been playing around with

    i basically have to take a word ( or serval words) and code them

    with an offset provided by the user so

    a=b is the 1st offset
    a=c is the 2nd offset

    and so on

    ive written this as a test , but it doesnt print the final word

    any help???

    ++++++++++++
    (btw... i know i havent covered all the possiblitties but this is just a test)++++++++++



    ************************************************** *******
    insert
    Code:
    #include<stdio.h>
    #include <string.h>
    
    #define size 3
    
    int  main (void)
    
    {
    		
    	char name[]= "aaa";		// setting name input
    	char new_name[size];	               // setting name output
    		
    	int pointer                                                //counter variable
    	int offset;				// setting variable for offset 
    
    	printf(" please enter in a offset" );
    	scanf("%d", &offset);
    	
    	switch (offset)
    
    	{
    		case 1:						
    //************* giving an offset of 1
    
    	for (pointer=0; pointer<=size ; pointer++)																			pointer = 0;
    
    		{	if (name[pointer] = 'a')
    				new_name[pointer] = 'b';
    
    			else if (name[pointer] ='b')
    				new_name[pointer] = 'c';
    
    			else if (name[pointer] = 'c')
    				new_name[pointer] = 'd';
    
    			else (name[pointer] = 'd');
    				new_name[pointer] = 'e';
    		}			
    			
    		printf(" the coding is %d", new_name);
    
    	break;
    
    
    
    		case 2:	
    	//**********giving an offset of 2
    
    	for (pointer=0; pointer<=size ; pointer++)																								// sum = the equation
    	pointer = 0;
    
    		{	if (name[pointer] = 'a')
    				new_name[pointer] = 'c';
    
    			else if (name[pointer] ='b')
    				new_name[pointer] = 'd';
    
    			else if (name[pointer] = 'c')
    				new_name[pointer] = 'e';
    
    			else (name[pointer] = 'd');
    				new_name[pointer] = 'f';
    		}			
    			
    		printf(" the coding is %d", new_name);
    			 
    	break;
    
    		case 3:						
    //************** giving an offset of 3
    
    	for (pointer=0; pointer<=size ; pointer++)																								// sum = the equation
    	pointer = 0;
    
    		{	if (name[pointer] = 'a')
    				new_name[pointer] = 'd';
    
    			else if (name[pointer] ='b')
    				new_name[pointer] = 'e';
    
    			else if (name[pointer] = 'c')
    				new_name[pointer] = 'f';
    
    			else (name[pointer] = 'd');
    				new_name[pointer] = 'g';
    		}			
    			
    		printf(" the coding is %d", new_name);
    			 
    	break;
    			default:
    			printf(" non valid offset") ;
    	}
    }

  2. #2
    and the hat of wrongness Salem's Avatar
    Join Date
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    First, enable some warnings in your compiler, so you can catch more problems before you run.
    Code:
    $ gcc -Wall foo.c
    foo.c: In function ‘main’:
    foo.c:27: warning: suggest parentheses around assignment used as truth value
    foo.c:30: warning: suggest parentheses around assignment used as truth value
    foo.c:33: warning: suggest parentheses around assignment used as truth value
    foo.c:40: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘char *’
    foo.c:52: warning: suggest parentheses around assignment used as truth value
    foo.c:55: warning: suggest parentheses around assignment used as truth value
    foo.c:58: warning: suggest parentheses around assignment used as truth value
    foo.c:65: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘char *’
    foo.c:75: warning: suggest parentheses around assignment used as truth value
    foo.c:78: warning: suggest parentheses around assignment used as truth value
    foo.c:81: warning: suggest parentheses around assignment used as truth value
    foo.c:88: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘char *’
    foo.c:94: warning: control reaches end of non-void function
    In particular, make sure case 1: works before copy/pasting mistakes into case 2 and case 3
    - You're using = where you should be using ==
    - You're using %d to print a string.

    > for (pointer=0; pointer<=size ; pointer++) pointer = 0;

    Does your editor have horizontal scroll bars?
    Because there is a bit of bad news stuck far to the right on this line.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  3. #3
    C++まいる!Cをこわせ! Elysia's Avatar
    Join Date
    Oct 2007
    Posts
    22,411
    Is this C or C++?
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

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