How do I remove a character from character array?

Yes those are places left by characters that you 'removed'. You will have to replace them with their neighbors.

By replacing them with their neighbors you mean pushing back all the characters after the space that were left? And I would do this with the 2nd char array?

Yes that is exactly what I mean. If you know exactly where you want to copy the next valid character though, then that would avoid the problem.

How would I copy the next valid character to a specific spot?

Keep track of the spot.

I just can't get it, how can I push back all of the characters after the space of the removed characters? I tried finding it in my book, and there is nothing like that. I tried looking online and can't find anything that relates to this. I've never done this before, I'm stuck!

Quote:

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Originally Posted by nick753

I've never done this before, I'm stuck!

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1) This is a bad attitude to have: at every point in your career, you will almost always be doing something you haven't done before. (If you had done it before, you'd just reuse the code and there you are.)

2) Have you read any posts in the thread other than your own? We've been pretty explicit on how to do this. You know where to start replacing, because that's where you found your letter. Every character after that, you need to move forward one space. So, do that.

Quote:

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Originally Posted by tabstop

1) This is a bad attitude to have: at every point in your career, you will almost always be doing something you haven't done before. (If you had done it before, you'd just reuse the code and there you are.)

2) Have you read any posts in the thread other than your own? We've been pretty explicit on how to do this. You know where to start replacing, because that's where you found your letter. Every character after that, you need to move forward one space. So, do that.

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I think my version is much easier, thanks for trying to help though!

Code:

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void remove(char cstring[], char letter)
{
int j = 0;
int i ;

for( i = 0; cstring[i] != '\0'; i++ )
{
cstring[j] = cstring[i];


if(cstring[i] != letter)
++j;       

}       
// terminate j
cstring[j] = '\0';
}

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Good, but you should indent your code properly:

Code:

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void remove(char cstring[], char letter)
{
    int j = 0;

    for (int i = 0; cstring[i] != '\0'; ++i)
    {
        cstring[j] = cstring[i];

        if (cstring[i] != letter)
            ++j;
    }

    // terminate j
    cstring[j] = '\0';
}

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Since i is only in the scope of the for loop, I have moved it to be local to the for loop. Finally, if you actually had to do this other than in an exercise, an appropriate solution would be to use a std::string, and then write:

Code:

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str.erase(std::remove(str.begin(), str.end(), 'l'), str.end());

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Code:

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void remove(char* input, char ch)
{
    char* output = input;
    while (*input)
    {
        if (*input != ch)
        {
            *(output++) = *input;
        }
        ++input;
    }
    *output = 0;
}

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Haven't read the replies.

Quote:

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Originally Posted by kmdv

Haven't read the replies.

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If you did you would have seen that your algorithm is essentially the same as the one nick753 implemented and posted in post #23.