add 2D array values

This is a discussion on add 2D array values within the C++ Programming forums, part of the General Programming Boards category; hi everyone! i have a problem with 2D array and tried this for 2 days. array is m*n and want ...

  1. #1
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    add 2D array values

    hi everyone!
    i have a problem with 2D array and tried this for 2 days.
    array is m*n and want to add values. explained in following example.

    1 2 3
    4 5 6
    7 8 9
    10 11 12

    outputs:
    1 + 4 + 7 + 10
    1 + 4 + 7 + 11
    1 + 4 + 7 + 12
    1 + 4 + 8 + 10
    1 + 4 + 8 + 11
    1 + 4 + 8 + 12
    1 + 4 + 9 + 10
    1 + 4 + 9 + 11
    1 + 4 + 9 + 12
    1 + 5 + 7 + 10
    1 + 5 + 7 + 11
    1 + 5 + 7 + 12
    1 + 5 + 8 + 10
    1 + 5 + 8 + 11
    1 + 5 + 8 + 12
    1 + 5 + 9 + 10
    1 + 5 + 9 + 11
    1 + 5 + 9 + 12
    1 + 6 + 7 + 10
    1 + 6 + 7 + 11
    1 + 6 + 7 + 12
    1 + 6 + 8 + 10
    1 + 6 + 8 + 11
    1 + 6 + 8 + 12
    1 + 6 + 9 + 10
    1 + 6 + 9 + 11
    1 + 6 + 9 + 12
    and in case of 2 and 3, add sequence are same as 1

    thanks

  2. #2
    and the hat of wrongness Salem's Avatar
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    So post your last best attempt at the solution.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  3. #3
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    i stopped the program it always resulted wrong
    it is making me crzay
    Code:
        int a[4][4]={{1,2,3,4},             //i mor
                     {5,6,7,8},             //j bagana
                     {9,10,11,12},
                     {13,14,15,16}};
                 
        int i1;
        int j1;
        int i=0,j=0,b[5][5],r,chose,sanakh=4,q,too=0,ber=0, save=0,horg=3,qwe=0,ewq=0;
    int sum[1000];
    for(int l = 0; l < 1000; l++)
    sum[l] = 0;
     //   while(1==1){
           //   for(j=0;j<=3;j++)
           //   {
                
                for(r=j;r<=3;r++)
                  {  for(q=0;q<=16;q++)
                  
                      {  save=0; top: for(i=0;i<=3;i++)
                                   {
                                               
                                   if(i<horg ) {save=save+a[i][r]; }
                                   if(horg==i && qwe==ewq)  {
                                                             for(int z=0;z<=3;z++)
                                                             {
                                                             sum[ber]=save+a[i][z];ber++;too++;
                                                             qwe++;
                                                            
                                                             }
                                                             save=0; 
                                                             horg--;
                                                             }
                                   else if (horg==i) {   sanakh=save;  
                                                         for (int t=r+1;t<=3;t++)
                                                         {
                                                              sanakh=save+a[i][t]; 
                                                              for(int d=0;d<=3;d++)
                                                                  {  
                                                                   cout<<sanakh<<"  ";
                                                                   sum[ber]=a[i+1][d]+sanakh; ber++;too++;
                                                                           
                                                                   } 
                                                              
                                                         }
                                                         
                                                         horg--;
                                                         if(i<4 )  {goto top;  }
                                                     }
                                   }
                                   sanakh--;          
                                   }             
               }
                                 int h=1;
                                  for(q=0;q<=30;q++)      { cout<<sum[q]<<" ";
                                  if (h==4){ cout<<endl;h=0;}h++;}

  4. #4
    and the hat of wrongness Salem's Avatar
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    Well the first thing is to learn the value of indentation.
    SourceForge.net: Indentation - cpwiki

    Here is your code, indented.
    Code:
    int a[4][4] = { {1, 2, 3, 4},   //i mor
    {5, 6, 7, 8},                   //j bagana
    {9, 10, 11, 12},
    {13, 14, 15, 16}
    };
    
    int i1;
    int j1;
    int i = 0, j = 0, b[5][5], r, chose, sanakh = 4, q, too = 0, ber =
        0, save = 0, horg = 3, qwe = 0, ewq = 0;
    int sum[1000];
    for (int l = 0; l < 1000; l++)
        sum[l] = 0;
     //   while(1==1){
           //   for(j=0;j<=3;j++)
           //   {
    
    for (r = j; r <= 3; r++) {
        for (q = 0; q <= 16; q++) {
            save = 0;
          top:
            for (i = 0; i <= 3; i++) {
                if (i < horg) {
                    save = save + a[i][r];
                }
                if (horg == i && qwe == ewq) {
                    for (int z = 0; z <= 3; z++) {
                        sum[ber] = save + a[i][z];
                        ber++;
                        too++;
                        qwe++;
                    }
                    save = 0;
                    horg--;
                } else if (horg == i) {
                    sanakh = save;
                    for (int t = r + 1; t <= 3; t++) {
                        sanakh = save + a[i][t];
                        for (int d = 0; d <= 3; d++) {
                            cout << sanakh << "  ";
                            sum[ber] = a[i + 1][d] + sanakh;
                            ber++;
                            too++;
                        }
                    }
    
                    horg--;
                    if (i < 4) {
                        goto top;
                    }
                }
            }
            sanakh--;
        }
    }
    
    int h = 1;
    for (q = 0; q <= 30; q++) {
        cout << sum[q] << " ";
        if (h == 4) {
            cout << endl;
            h = 0;
        }
        h++;
    }
    next_permutation
    Create an array called
    Code:
    row_index[4] = { 0, 1, 2, 3 };
    Create another called
    Code:
    col_index[4] = { 0, 1, 2, 3 };
    For each permutation of row_index, you permute all of col_index

    For all of that, you do
    Code:
    for ( i = 0 ; i < 4 ; i++ ) 
      sum += a[row_index[i]][col_index[i]];
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  5. #5
    C++ Witch laserlight's Avatar
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    Unfortunately, note that Salem's suggestion of next_permutation is from the C++ standard library; in C you have to implement the algorithm yourself.
    C + C++ Compiler: MinGW port of GCC
    Version Control System: Bazaar

    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  6. #6
    a_capitalist_story
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    And...another cross-poster.

  7. #7
    and the hat of wrongness Salem's Avatar
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    Mmm, this is indeed the C forum, yet the code has cout calls.
    Moved.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  8. #8
    and the hat of wrongness Salem's Avatar
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    This is probably spoon-feeding, but
    Code:
    #include <iostream>
    #include <iomanip>
    #include <algorithm>
    using namespace std;
    
    int main ( ) {
      int a[4][4] = {
        {1, 2, 3, 4},
        {5, 6, 7, 8},
        {9, 10, 11, 12},
        {13, 14, 15, 16}
      };
      int row_index[] = { 0, 1, 2, 3 };
      int col_index[] = { 0, 1, 2, 3 };
      const int N = sizeof(row_index) / sizeof(row_index[0]);
      
      do {
        do {
          for ( int i = 0 ; i < N ; i++ ) {
            cout << "a[" << row_index[i] << "]["<< col_index[i] << "]";
            if ( i == N-1 ) cout << endl; else cout << "+";
          }
        } while ( next_permutation(col_index, col_index+N) );
      } while ( next_permutation(row_index, row_index+N) );
    
      return 0;
    }
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

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