help in c++ while

i have this program when i press 6 the program should exit why is this not working. when i press 6 i get garbage value is my logic right

Code:

#include <iostream> 

using namespace std; 
template <typename mytype>
mytype fun (mytype a, mytype b, mytype c)
{
      if(b>c)
      {
             
        return(b);     
      }
      
      

}

int main () 
{ 

int a,b,c,select;
cout << "Types of gates available:"<<'\n';
cout << "1. And"<<'\n';
cout << "2. Or"<<'\n';
cout << "3. And"<<'\n';
cout << "4. Or"<<'\n';
cout << "5. And"<<'\n';
cout << "6. exit"<<'\n';

cout << "Select gate #1"<<'\n'; 
cin>>a;
while(!a==6)
{
cout<<"Enter two inputs for gates =>"<<'\n';
cin>>b;
cin>>c;
}



cout<<fun(a,b,c);


          cin.sync();
          cin.get();

          return 0; 
}

> while(!a==6)

Maybe
a != 6

or

! ( a == 6 )

And would it kill you to indent you code?
http://sourceforge.net/apps/mediawik...le=Indentation

it doesnt work. you just guessing

That's just rude. And Salem was absolutely right in that was an error in your code. It's just not the only one. For example, your while-loop, once entered, cannot possibly terminate. Also, your program flow is a mess and doesn't do what you want at all, because your loop spans the wrong instructions.

if you start a loop

Code:

while(a != 6) // salem was right about how to put that
{
  cout<<"Enter two inputs for gates =>"<<'\n';
  cin>>b;
  cin>>c;
}

and never assign a new variable to (a) within the loop. Then you are never going to leave that loop.
1. Initial requirement a doesn't equal 6
2. cout stuff
3. change b value
4. change c value
5. end of loop and a still doesn't equal 6 start loop again
6. cout stuff
7. change b value
8. change c value
9. a still doesn't equal 6
......... ect.
See where thats goin? (somewhere there needs to be a ... change a value)
You have to be careful with any while loop to set a condition that can actually allow you to exit the loop, or the computer gets stuck there indefinitely.

On the other hand, if a is 6 the first time through, you never read values for b and c, which is why they're garbage.

indeed

Originally Posted by mouse666666

it doesnt work. you just guessing

So you think because he used the word "maybe" he's guessing?! You're wrong in that assumption. It looks like "maybe" was being used in a sarcastic tone. I say that because he is in fact completely right.
Here's a table of operator precedence for you to look at.

What you wrote was equivalent to (!a) == 6 and your logic is most definitely wrong.

Originally Posted by mouse666666

it doesnt work. you just guessing

ah...what a very interesting response, now I can't wait to see what will happen

Like I'm going to pay any attention to a coder who's approach to programming is "smash face into keyboard until knowledge is absorbed".