Thread: help with "function does not take 1 arguments"

  1. #1
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    Aug 2010
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    Question help with "function does not take 1 arguments"

    I am only getting the 1 error "function does not take 1 arguments mean?" on my bubblesort algorithm.
    what does this mean?!
    i believe the bit its having trouble with is line
    Code:
    bubblesort(A);
    where i call my function bubblesort to work on array A[]
    but just incase, here is my top part
    Code:
    #include <iostream>
    using namespace std;
    
    const int numberofintegers=1000;
    int G=0;
    void bubblesort(int A[], int G);
    int A[numberofintegers];
    and my function at the bottom
    Code:
    void bubblesort(int A[], int G){
    	int Q, W, E;
    	for (int Q=0; Q<G; Q++){
    		for (int W=0; W<G-1; W++){
    			if (A[W+1]<A[W]){
    				E = A[W+1];
    				A[W+1]=A[W];
    				A[W]=E;
    			}
    		}
    	}
    }
    im sorry if this isnt a correct way to post, im new, but any help you could give me would be greatly appreciated. thanks.

  2. #2
    Just a pushpin. bernt's Avatar
    Join Date
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    function does not take 1 arguments mean
    It means the function takes a number of arguments not equal to 1. It's actually a pretty self-explanatory message. Much better than a segmentation violation, by any measure.

    Code:
    void bubblesort(int A[], int G);
    ...
    bubblesort(A);
    Notice how bubblesort is defined with two arguments, yet you call it with one? That's the problem.
    Consider this post signed

  3. #3
    Registered User
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    oh, so can i change

    Code:
    bubblesort(A);
    to
    Code:
    bubblesort(A,G);
    ?

  4. #4
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    cheers man, sorry for any stupid questions, thanks for not replying and taking the ........ with stupid answers
    Last edited by Salem; 08-29-2010 at 10:39 PM. Reason: Language

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