Thread: close on command

The console window will close once the main function ends. That's all.

Okay hmm...then maybe if i post my code it will help.
I am figuring its the break; command,but i'm not sure how to go about it without having an infinite loop

Code:

#include "stdafx.h"
#include <iostream>

using namespace std;

int main()
{
	int num;
	cout << "Enter any number other than 5" << endl;

	cin >> num;
	for(;;)
	{
		
		
		if(num == 5)

			cout << "Hey! you werent supposed to enter 5!" << endl;
		else
		cout << "Enter any number other than 5" << endl;
		break;
	}
	char f;
	cin >> f;
	return 0;
}

You should put in a specific count to end the for loop

Also not sure why you made your code that way, you should maybe make a loop with ev erything inside(not one input outside and the a never ending loop for the rest)

I would do something along the lines of:

Code:

int choice=0;
int main(){
    for(int count=15;count!=0;count--;){
        cout<<"Enter a number, other than 5";
        cin>>choice
        if(choice==5){cout<<"I said not 5!"}
    }
}

Code:

		else
		cout << "Enter any number other than 5" << endl;
		break;

Contrary to what you might think, the break isn't part of the else statement.
Use braces to put more than one line inside an else block.
As it is, the break will always break your loop after the first iteration in your code.