Is an anonymous union standard C and standard C++ ?
Looks to me not standard C but only C++. Is that right?
Is an anonymous union standard C and standard C++ ?
Looks to me not standard C but only C++. Is that right?
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.