Thread: Number of bytes in an EOF?

I've been noticing the gap between characters read and the file size on my XP system with a loop I just have go through a text file and read characters.

Is EOF OS/Implementation specific? So far from what I calculated from the input filesize is 1210, the # of characters is 1188 which leaves 22 bytes unaccounted for. Here's the code

Code:

void rput_readfilev2(int a, _TCHAR * ar[])
{
	 int elapTicks;
     double elapMilli, elapSeconds, elapMinutes;
     clock_t Begin, End;             //initialize Begin and End for the timer

	 /*
     Begin = clock() * CLK_TCK;      //start the timer  
     for(int a=1; a<=10000; a++);
     End = clock() * CLK_TCK;        //stop the timer 
     */   
     
    

	ifstream fin;
	ofstream fout;
	long count2 =0;
	long count;
	long total = 0;
	int ch;

	int spaces=0;
	int newlines=0;
	int style =0;

	// fout.open(ar[2]);  Open filename2(argument #2) for output
	int file = 1;
		
	Begin = clock() * CLK_TCK;
	
	fin.open(ar[file]);


	count = 0;
	cout << file << " \n";
	ch = fin.get();
	while ( ch != EOF)  // While ch does not equal end of file, while quites if ch is EOF (end of file)
	{
		ch = fin.get();
		/*cout << " 1. m " << count << "\n";*/
		if (ch ==' ')
			spaces++;
		else if (ch == '\n')
			newlines++;
		cout << ch << "	    \n";
		count++;
	}

	cout << "\n";
	cout << "\nThere was " << count << " characters in \n" ;
	wcout << "Argument 1 : " << ar[1] << " \n";
	total +=count;
	fin.clear();
	fin.close();
	// fout.close();  Closing the output file