okay when if its okay with u ill write post the instructions so it be clearer than me explaing\
By calling the function smatrix(A,x,n),with n=4,
which you will construct, determine the components of the matrix A_s=(A+A_t)/2, where
A_t stands for the transpose matrix of A, and the components of the
vector y=(A_s*x)/norm_x, where norm_x denotes the norm (length) of the vector x.
Print the components of the matrix A_s and the vector y in the main.
Free dinamically allocated memory
oh oops then its c sorry for the mistake, i guess i should have posted this in the other forum
i feel dumb now
It doesn't matter that much, as long as you are sure which way you are suppose to go.Originally Posted by rafacnsoccer
I don't know much about math, can you do this on paper? As for this bit:
That means smatrix will either return a **double (a new matrix), or else it could change A in place (if that is feasible). If you don't need to use the original A again, changing in place would be better (but it might be impossible depending on the details of the math part).
C programming resources:
GNU C Function and Macro Index -- glibc reference manual
The C Book -- nice online learner guide
Current ISO draft standard
CCAN -- new CPAN like open source library repository
3 (different) GNU debugger tutorials: #1 -- #2 -- #3
cpwiki -- our wiki on sourceforge
see i look online and all i find are programs using this type of transpose, which i dnt know if its the same
insertCode:int main() { int i,j; double a[4][5] = {{ 1.00, 2.00, 3.00, 4.00, 5.00}, { 1.00, 4.00, 9.00, 16.00, 25.00}, { 1.00, 8.00, 27.00, 64.00,125.00}, { 1.00, 16.00, 81.00,256.00,625.00}}; double b[5][4]; transpose_matrix(&a[0][0], &b[0][0], 4, 5); for(j=0;j<4;j++) { for(i=0;i<5;i++) { printf("%6.2lf ", a[j][i]); } printf("\n"); } printf("--\n"); for(j=0;j<5;j++) { for(i=0;i<4;i++) { printf("%6.2lf ", b[j][i]); } printf("\n"); } }
yea so i am not too sure how to much on or how to translate this using the file pointer
