Ok this is the code.Code:#include <iostream.h> int main() { int i=0, j=0; char s1[40]="string 1", s2[35]="string 2", st[75]; while(s1[i]) { st[i]=s1[i]; ++i; } while ((*(st+i)=s2[j]) !=0) { ++i; ++j; } cout <<st; }
In this peace of code i dont understand what the '*' is doing and i dont understand why is it important, but when i remove it the compiler returns an error.Code:while ((*(st+i)=s2[j]) !=0) { ++i; ++j; }
Can someone tell me pls what is that '*' for??
Tks
Array and pointer notation are closely associated with one another (note: this is not saying that arrays and pointers are the same thing - they're not).
But
*( array + index ) is just another way of saying array[index]
> #include <iostream.h>
You might want to get a more modern C++ compiler, if these are the header files you're including.
Modern C++ has
#include <iostream>
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
It's "de-referencing" a pointer. You have a pointer pointing at a location in memory, to access the thing it is pointing to, you need to de-reference it.
Tks dudes, i got the ideaand ty for the sugestion Salem.
